public class BinaryTreeInorderTraversal { private class TreeNode { int val; TreeNode left; TreeNode right; TreeNode(int x) { val = x; } } /*public List<Integer> inorderTraversal(TreeNode root) { List<Integer> list = new ArrayList<>(); addNode(list,root); return list; } public vo...
1/**2* Definition for binary tree3* struct TreeNode {4* int val;5* TreeNode *left;6* TreeNode *right;7* TreeNode(int x) : val(x), left(NULL), right(NULL) {}8* };9*/10classSolution {11public:12vector<int> inorderTraversal(TreeNode *root) {13//IMPORTANT: Please reset any ...
Given a binary tree, return the inorder traversal of its nodes' values. For example: Given binary tree [1,null,2,3], return [1,3,2]. Note: Recursive solution is trivial, could you do it iteratively? 解析 嘻嘻,最近因为马上要面试,就回忆一下树的遍历,快排,最长公共子序列,八皇后之类的基...
classSolution{publicList<Integer>inorderTraversal(TreeNode root){List<Integer>list=newArrayList<>();//数组if(root==null)returnlist;Stack<TreeNode>stack=newStack<>();//用数据结构栈暂存节点TreeNode cur=root;//定义当前节点while(!stack.isEmpty()||cur!=null){//循环条件:栈不空或当前节点不空if(...
Leetcode 94: Binary Tree Inorder Traversal-中序遍历 自动驾驶搬砖师 一步一个台阶,一天一个脚印 一、题目描述 给定一个二叉树,返回它的中序遍历。 二、解题思路 2.1 递归法 时间复杂度 O(n) 空间复杂度 O(n) 2.2 迭代法 时间复杂度 O(n) 空间复杂度 O(n)(...
94. Binary Tree Inorder TraversalEasy Topics Companies Given the root of a binary tree, return the inorder traversal of its nodes' values. Example 1: Input: root = [1,null,2,3] Output: [1,3,2] Explanation: Example 2: Input: root = [1,2,3,4,5,null,8,null,null,6,7,9] ...
TreeNode *t = stk.top(); rs.push_back(t->val); stk.pop(); flag = true; if (t->right) { stk.push(t->right); flag = false; } } return rs; } 或者如下,leetcode上解说的算法: vector<int> inorderTraversal(TreeNode *root) ...
TreeNode curr = s.pop(); res.add(curr.val); if(curr.right!=null) s.push(curr.right); if(curr.left!=null) s.push(curr.left); } return res; } } Binary Tree Inorder Traversal Given a binary tree, return the inorder traversal of its nodes' values. ...
Given a binary tree, return the level order traversal of its nodes' values. (ie, from left to right, level by level). For example: Given binary tree [3,9,20,null,null,15,7], 代码语言:javascript 代码运行次数:0 运行 AI代码解释 ...
preorder = [3,9,20,15,7] inorder = [9,3,15,20,7] 1. 2. Return the following binary tree: 3 / \ 9 20 / \ 15 7 1. 2. 3. 4. 5. 题目大意 使用先序遍历和中序遍历序列重构二叉树。 解题方法 递归 解决本题需要牢牢掌握先序遍历和中序遍历的含义,以及递归。