public class Binary_Tree_Postorder_Traversal { public static class TreeNode { int val; TreeNode left; TreeNode right; TreeNode(int x) { val = x; } } public static void main(String[] args) { TreeNode r1 = new TreeNode(1); TreeNode r2 = new TreeNode(2); TreeNode r3 = new Tree...
1#Definition for a binary tree node.2#class TreeNode(object):3#def __init__(self, x):4#self.val = x5#self.left = None6#self.right = None78classSolution(object):9defpostorderTraversal(self, root):10"""11:type root: TreeNode12:rtype: List[int]13"""14res =[]15tmp =[]16flag...
94. Binary Tree Inorder TraversalEasy Topics Companies Given the root of a binary tree, return the inorder traversal of its nodes' values. Example 1: Input: root = [1,null,2,3] Output: [1,3,2] Explanation: Example 2: Input: root = [1,2,3,4,5,null,8,null,null,6,7,9] ...
** Inorder Traversal: left -> root -> right ** Preoder Traversal: root -> left -> right ** Postoder Traveral: left -> right -> root 记忆方式:order的名字指的是root在什么位置。left,right的相对位置是固定的。 图片来源:https://leetcode.com/articles/binary-tree-right-side-view/ ...
此时执行到 preorderTraversal(node.left, list)这一行,在这里调用了一个方法——preorderTraversal(TreeNode node, List<Integer> list)。而这个方法比较特殊。因为是他自己。就是自己调用自己。那么程序执行到这时,就会停止继续向下一行执行。而是进入到preorderTraversal(TreeNode node, List<Integer> list)方法内部...
102. 二叉树的层序遍历 - 给你二叉树的根节点 root ,返回其节点值的 层序遍历 。 (即逐层地,从左到右访问所有节点)。 示例 1: [https://assets.leetcode.com/uploads/2021/02/19/tree1.jpg] 输入:root = [3,9,20,null,null,15,7] 输出:[[3],[9,20],[15,7]]
105. 从前序与中序遍历序列构造二叉树 - 给定两个整数数组 preorder 和 inorder ,其中 preorder 是二叉树的先序遍历, inorder 是同一棵树的中序遍历,请构造二叉树并返回其根节点。 示例 1: [https://assets.leetcode.com/uploads/2021/02/19/tree.jpg] 输入: preo
Can you solve this real interview question? Binary Tree Postorder Traversal - Given the root of a binary tree, return the postorder traversal of its nodes' values. Example 1: Input: root = [1,null,2,3] Output: [3,2,1] Explanation: [https://assets
The function returns the root of the constructed binary tree. 4. Time & Space Complexity Analysis: 4.1 Time Complexity: 4.1.1 Lists as parameters In each recursive call, the index() function is used to find the index of the root value in the inorder traversal list. This function has a ...
Leetcode 94: Binary Tree Inorder Traversal-中序遍历 自动驾驶搬砖师 一步一个台阶,一天一个脚印 一、题目描述 给定一个二叉树,返回它的中序遍历。 二、解题思路 2.1 递归法 时间复杂度 O(n) 空间复杂度 O(n) 2.2 迭代法 时间复杂度 O(n) 空间复杂度 O(n)(1) 同理创建一个Stack,然后按左/中/右...