3.线索二叉树 ref:Morris Traversal方法遍历二叉树(非递归,不用栈,O(1)空间) wiki:Threaded binary tree A binary tree isthreadedby making all right child pointers that would normally be null point to the inorder successor of the node (ifit exists), and all left child pointers that would normall...
classSolution(object):definorderTraversal(self, root):#递归""":type root: TreeNode :rtype: List[int]"""ifnotroot:return[]returnself.inorderTraversal(root.left) + [root.val] + self.inorderTraversal(root.right) Java解法 classSolution {publicList < Integer >inorderTraversal(TreeNode root) ...
Given the root of a binary tree, return the inorder traversal of its nodes' values. Example 1: Input: root = [1,null,2,3] Output: [1,3,2] Example 2: Input: root = [] Output: [] Example 3: Input: root = [1] Output: [1] Constraints: The number of nodes in the tree is...
Leetcode 94: Binary Tree Inorder Traversal-中序遍历 自动驾驶搬砖师 一步一个台阶,一天一个脚印 一、题目描述 给定一个二叉树,返回它的中序遍历。 二、解题思路 2.1 递归法 时间复杂度 O(n) 空间复杂度 O(n) 2.2 迭代法 时间复杂度 O(n) 空间复杂度 O(n)(1) 同理创建一个Stack,然后按左/中/右...
请一键三连, 非常感谢LeetCode 力扣题解94. 二叉树的中序遍历94. Binary Tree Inorder Traversal帮你深度理解 二叉树 数据结构 递归算法 Morris遍历 迭代, 视频播放量 116、弹幕量 0、点赞数 0、投硬币枚数 0、收藏人数 0、转发人数 0, 视频作者 程序员写代码, 作者简介 Lee
初始栈空,开...Leetcode 94. Binary Tree Inorder Traversal二叉树中序遍历 Given a binary tree, return the inorder traversal of its nodes' values. Example: 题目链接:https://leetcode.com/problems/binary-tree-inorder-traversal/ 顺便提醒一下自己,从明天开始,系统地学学GitHub的使用 ......
【LeetCode】 94. Binary Tree Inorder Traversal 二叉树的中序遍历(Medium)(JAVA) 题目地址: https://leetcode.com/problems/binary-tree-inorder-traversal/ 【LeetCode】 144. Binary Tree Preorder Traversal 二叉树的前序遍历(Medium)(J...leetcode 94. Binary Tree Inorder Traversal中序遍历 我特么要...
94. Binary Tree Inorder TraversalEasy Topics Companies Given the root of a binary tree, return the inorder traversal of its nodes' values. Example 1: Input: root = [1,null,2,3] Output: [1,3,2] Explanation: Example 2: Input: root = [1,2,3,4,5,null,8,null,null,6,7,9] ...
vector<int> inorderTraversal(TreeNode* root) { vector<int> res; inorder(res,root); return res; } private: void inorder(vector<int>& res,TreeNode* root){ if(root==NULL) return; inorder(res,root->left); res.push_back(root->val); ...
94. Binary Tree Inorder Traversal,两种解法,递归和迭代Memory分别是6.1和5.7,速度好像是一样的。。RecursiveclassSolution{public:vector<int>res;voidin_order(TreeNode*root){if(!root)return;in_order(root->left);res.push_back(root-&...