{intiLeftHeight =0;intiRightHeight =0;if(!root)return0;if(!root->left && !root->right)return1;if(root->left) { iLeftHeight= getBinTreeHeight(root->left); }if(root->right) { iRightHeight= getBinTreeHeight(root->right); }return(MAX_INT(iLeftHeight, iRightHeight) +1); }/** ...
a binary tree in which the left and right subtrees of every node differ in height by no more than 1. 英文版地址 leetcode.com/problems/b 中文版描述 给定一个二叉树,判断它是否是高度平衡的二叉树。本题中,一棵高度平衡二叉树定义为:一个二叉树每个节点 的左右两个子树的高度差的绝对值不超过 1 ...
力扣leetcode-cn.com/problems/diameter-of-binary-tree/ 题目描述 给定一棵二叉树,你需要计算它的直径长度。一棵二叉树的直径长度是任意两个结点路径长度中的最大值。这条路径可能穿过也可能不穿过根结点。 示例: 给定二叉树 1 / \ 2 3 / \ 4 5 返回3, 它的长度是路径 [4,2,1,3] 或者 [5...
【leetcode】Balanced Binary Tree Given a binary tree, determine if it is height-balanced. For this problem, a height-balanced binary tree is defined as a binary tree in which the depth of the two subtrees ofeverynode never differ by more than 1. 题解: 一种方法是写一个递归求高度的函数...
来源:力扣(LeetCode) 链接:https://leetcode-cn.com/problems/maximum-depth-of-binary-tree/ 解题思路 递归DFS(深度优先搜索 Depth-First-Search) : 首先,我们要知道一棵树的最大深度在逻辑上怎么求? 树的最大深度 = 根节点的高度(根本身为 1 )+ 左右子树的最大深度中的较大者。
Given a binary tree, determine if it is height-balanced. For this problem, a height-balanced binary tree is defined as: a binary tree in which the depth of the two subtrees of every node never differ by more than 1. 1. Example 1: ...
空间复杂度:O(height),其中 height 表示二叉树的高度。递归函数需要栈空间,而栈空间取决于递归的深度,因此空间复杂度等价于二叉树的高度。 三、方法二 通过层序遍历来判断高度 /** * Definition for a binary tree node. * public class TreeNode {
Left) rh := height(node.Right) if lh+rh+1 > path { path = lh + rh + 1 } if lh > rh { return lh + 1 } return rh + 1 } func diameterOfBinaryTree(root *TreeNode) int { path = 0 height(root) return path - 1 } 参考文献 543. 二叉树的直径- LeetCode 本文参与 腾讯云...
第C++实现LeetCode(108.将有序数组转为二叉搜索树)[LeetCode]108.ConvertSortedArraytoBinarySearchTree将有序数组转为二叉搜索树 Givenanarraywhereelementsaresortedinascendingorder,convertittoaheightbalancedBST. Forthisproblem,aheight-balancedbinarytreeisdefinedasabinarytreeinwhichthedepthofthetwosubtreesofeverynode...
* Definition for a binary tree node. * struct TreeNode { * int val; * TreeNode *left; * TreeNode *right; * TreeNode(int x) : val(x), left(NULL), right(NULL) {} * }; */ class Solution { public: TreeNode* lowestCommonAncestor(TreeNode* root, TreeNode* p, TreeNode* q) {...