publicintmaxProfit(int[] prices){if(prices ==null|| prices.length <=1) {return0; }intmaxProfit = Integer.MIN_VALUE;intbuyPrice = prices[0];for(inti=1; i < prices.length; i++) {if(prices[i] > buyPrice) { maxProfit = Math.max(maxProfit, prices[i]-buyPrice); }else{ buyPrice ...
【leetcode】41-best-time-to-buy-and-sell-stock-ii 力扣 122. 买卖股票的最佳时机 II 【leetcode】42-best-time-to-buy-and-sell-stock-iii 力扣 123. 买卖股票的最佳时机 III 【leetcode】43-best-time-to-buy-and-sell-stock-iv 力扣 188. 买卖股票的最佳时机 IV 【leetcode】44-best-time-to-bu...
LeetCode 122:买卖股票的最佳时机 II(Best Time to Buy and Sell Stock II) 交易次数限制:允许进行多次买卖操作。你可以尽可能地完成更多的交易,但是你不能同时参与多笔交易(即你必须在再次购买前出售掉之前的股票)。 目标:求得最大利润。这里的最大利润是所有可能交易的利润之和。 这个问题的核心在于利用每一次...
Can you solve this real interview question? Best Time to Buy and Sell Stock - You are given an array prices where prices[i] is the price of a given stock on the ith day. You want to maximize your profit by choosing a single day to buy one stock and choo
122. Best Time to Buy and Sell Stock II Say you have an array for which theith element is the price of a given stock on dayi. Design an algorithm to find the maximum profit. You may complete as many transactions as you like (ie, buy one and sell one share of the stock multiple ...
Can you solve this real interview question? Best Time to Buy and Sell Stock - You are given an array prices where prices[i] is the price of a given stock on the ith day. You want to maximize your profit by choosing a single day to buy one stock and choo
题目:Best Time to Buy and Sell Stock Say you have an array for which theithelement is the price of a given stock on dayi. If you were only permitted to complete at most one transaction (ie, buy one and sell one share of the stock), design an algorithm to find the maximum profit....
LeetCode: 121. Best Time to Buy and Sell Stock 题目描述 Say you have an array for which the ith element is the price of a given stock on day i. If you were only permitted to complete at most one transaction (ie, buy one and sell one share of the stock), design an algorithm to...
https://leetcode.com/problems/best-time-to-buy-and-sell-stock-ii/ 因为可以进行无限次交易,并且在下一次buy之前必须已经sell。所以只需要把所有price曲线价格上涨的部分加起来就行。 class Solution(object): def maxProfit(self, prices): """
这道题目还有两个变体,Best Time to Buy and Sell Stock II和Best Time to Buy and Sell Stock III,虽然题目要求比较像,但是思路却变化比较大,Best Time to Buy and Sell Stock II可以交易无穷多次,思路还是比较不一样,而Best Time to Buy and Sell Stock III则限定这道题交易两次,其实还可以general到限定...