Say you have an array for which the ith element is the price of a given stock on day i. Design an algorithm to find the maximum profit. You may complete at most two transactions. Note: You may not engage in multiple transactions at the same time (ie, you must sell the stock before ...
Design an algorithm to find the maximum profit. You may complete as many transactions as you like (ie, buy one and sell one share of the stock multiple times). However, you may not engage in multiple transactions at the same time (ie, you must sell the stock before you buy again). 2...
https://leetcode.com/problems/best-time-to-buy-and-sell-stock-iv/ Say you have an array for which the ith element is the price of a given stock on day i. Design an algorithm to find the maximum profit. You may complete at most k transactions. Solution global(n, k) 表示前n天中一...
:rtype: int"""res=0foriinrange(1,len(prices)): temp= prices[i] - prices[i-1]iftemp <=0:continueelse: res+=tempreturnres 参考: 下面的更快,因为索引查找的次数少一些! classSolution(object):defmaxProfit(self, prices):""":type prices: List[int] :rtype: int"""iflen(prices) ==0:...
Explanation: transactions = [buy, sell, cooldown, buy, sell] 题目如下:本题和【leetcode】714. Best Time to Buy and Sell Stock with Transaction Fee几乎是一样的,一个是有交易手续费,一个是有CD时间。在【leetcode】714. Best Time to Buy and Sell Stock with Transaction Fee的基础上,dp[i][0...
Best time to buy and sell stocks IV 题目 https://leetcode.com/problems/best-time-to-buy-and-sell-stock-iv/ Say you have an array for which the ith element is the price of a given stock on day i. Design an algorithm to find the maximum profit....
View Code 别人代码: View Code 学习之处: diff的变量命名不错 if(null==stocks || stocks.length==0) return 0; int maxProfit = 0 ; int cur = stocks[0]; for(int stock : stocks){ if(stock > cur) maxProfit += (stock-cur);
You may not engage in multiple transactions at the same time (ie, you must sell the stock before you buy again). 2.解法分析 限定了交易次数之后题目就需要我们略微思考一下了,由于有两次交易的机会,那么我们选定一个时间点ti,将此时间点作为两次交易的支点的话,必然有: ...