If x == y, both stones are destroyed, andIf x != y, the stone of weight x is destroyed, and the stone of weight y has new weight y - x.At the end of the game, there is at most one stone left.Return the smallest possible weight of the left stone. If there are no stones l...
代码(Python3) class Solution: def lastStoneWeight(self, stones: List[int]) -> int: # 由于 heapq 默认是最小堆,所以这里取相反数进行转换 heap: List[int] = [-num for num in stones] # 通过数组直接建立堆 heapq.heapify(heap) # 至少还有两个数字时,继续循环处理 while len(heap) > 1: # ...
最后判断队列是否为空,为空就返回0,不为空就返回队首的元素值。 publicintlastStoneWeight3(int[] stones){ PriorityQueue<Integer> pq =newPriorityQueue<>(Comparator.reverseOrder());for(intstone : stones) { pq.offer(stone); }while(pq.size() >1) {intnum=pq.poll() - pq.poll();if(num >0)...
AC Java: 1classSolution {2publicintlastStoneWeight(int[] stones) {3if(stones ==null|| stones.length == 0){4return0;5}67PriorityQueue<Integer> maxHeap =newPriorityQueue<>(Collections.reverseOrder());8for(intstone : stones){9maxHeap.add(stone);10}1112while(maxHeap.size() > 1){13intx...
classSolution:deflastStoneWeight(self,stones:list[int])->int:whileTrue:iflen(stones)<=1:breakstones.sort()m1=stones.pop()m2=stones.pop()temp=m1-m2iftemp>=0:stones.append(temp)iflen(stones)==1:r=stones[0]else:r=0returnrif__name__=='__main__':s=Solution()data=[2,7,4,1,8,...
You are given an array of integers stones where stones[i] is the weight of the ith stone. We are playing a game with the stones. On each turn, we choose any two stones and smash them together. Suppose the stones have weights x and y with x <= y. The result of this smash is: ...
1049. Last Stone Weight II刷题笔记 class Solution: def lastStoneWeightII(self, stones: List[int]) -> int: sumweight = sum(stones) target = sumweight//2 dp = [0]*(target+1) for i in range(len(stones)): for j in range(target,stones[i]-1,-1):...
1046. Last Stone Weight We have a collection of rocks, each rock has a positive integer weight. Each turn, we choose the two heaviest rocks and smash them together. Suppose the stones have weightsxandywithx <= y. The result of this smash is:...
1049. Last Stone Weight II # 题目 # We have a collection of rocks, each rock has a positive integer weight. Each turn, we choose any two rocks and smash them together. Suppose the stones have weights x and y with x <= y. The result of this smash is: I
Read the full-text online article and more details about DIET COACH: How Can I Shift That Last Stone of Weight? Diet Coach JUDY CITRON Answers All Your Dieting Questions to Help You Get into Shape.Sunday Mercury (Birmingham, England)Sunday Mercury...