Java publicintlastStoneWeightII(int[] stones){intsum=0;for(intstone : stones) { sum += stone; }inttarget=sum /2;int[] dp =newint[target +1];intn=stones.length;for(inti=0; i < n; i++) {for(intj=target; j >= stones[i]; j--) { dp[j] = Math.max(dp[j], dp[j - ...
class Solution { public: int lastStoneWeightII(vector<int>& stones) { int sum = 0; for (int i = 0; i < stones.size(); ++i) { sum += stones[i]; } int total_sum = sum; sum /= 2; int n = stones.size(); int dp[n+1][sum+1]; for (int i = 0; i < n; ++i) ...
class Solution{public:intlastStoneWeightII(vector<int>&stones){intsum=accumulate(stones.begin(),stones.end(),0);vector<int>dp((sum>>1)+1);for(constauto&stone:stones)for(intj=(sum>>1);j>stone-1;j--)dp[j]=max(dp[j],dp[j-stone]+stone);returnsum-(dp[(sum>>1)]<<1);}}; J...
1049. Last Stone Weight II刷题笔记 class Solution: def lastStoneWeightII(self, stones: List[int]) -> int: sumweight = sum(stones) target = sumweight//2 dp = [0]*(target+1) for i in range(len(stones)): for j in range(target,stones[i]-1,-1): dp[j] = max(dp[j],dp[j-...
publicintlastStoneWeightII(int[]stones){intn=stones.length;intsum=0;for(intnum:stones)sum+=num;int[]dp=newint[sum/2+1];dp[0]=1;for(inti=0;i<n;i++){for(intw=sum/2;w>=0;w--){if(stones[i]<=w)dp[w]=dp[w]+dp[w-stones[i]];}}intres=Integer.MAX_VALUE;for(inti=0;i...
classSolution{publicintlastStoneWeightII(int[]stones){if(stones.length==1)returnstones[0];intsum=0;for(intn:stones)sum+=n;Arrays.sort(stones);// sort array for de-duplication and for pruningint[]closest=newint[1];findClosestFloor(stones,0,closest,sum/2,0);returnsum-2*closest[0];}pri...
func lastStoneWeight(stones []int) int { // 通过数组直接建立堆 q := IntHeap(stones) heap.Init(&q) // 至少还有两个数字时,继续循环处理 for len(q) > 1 { // 获取最大数字 y := heap.Pop(&q).(int) // 获取次大数字 x := heap.Pop(&q).(int) // 如果 x != y ,则再将 y...
链接:https://leetcode-cn.com/problems/last-stone-weight 提示 为了实现全局最小,首先从实现局部最小开始吧 本题关键字:贪心算法,优先队列 解析 思路 对于每一个stone, s,为了使相减结果最小,我们必然要寻找重量最接近s的另一个stone,且由于选大选小关系不方便判断,可以尝试从最大的s开始计算起(因为此时重量...
packageleetcodefunclastStoneWeightII(stones[]int)int{sum:=0for_,v:=rangestones{sum+=v}n,C,dp:=len(stones),sum/2,make([]int,sum/2+1)fori:=0;i<=C;i++{ifstones[0]<=i{dp[i]=stones[0]}else{dp[i]=0}}fori:=1;i<n;i++{forj:=C;j>=stones[i];j--{dp[j]=max(dp[...
Read the full-text online article and more details about DIET COACH: How Can I Shift That Last Stone of Weight? Diet Coach JUDY CITRON Answers All Your Dieting Questions to Help You Get into Shape.Sunday Mercury (Birmingham, England)Sunday Mercury...