For example, given[3, 30, 34, 5, 9], the largest formed number is9534330. Note: The result may be very large, so you need to return a string instead of an integer. python code: class Solution: # @param num, a list of integers # @return a string def largestNumber(self, num): ...
https://oj.leetcode.com/problems/largest-number/ Given a list of non negative integers, arrange them such that they form the largest number. For example, given [3, 30, 34, 5, 9], the largest formed number is 9534330. Note: The result may be very large, so you need to return a s...
https://leetcode.com/problems/largest-number/discuss/53298/Python-different-solutions-(bubble-insertion-selection-merge-quick-sorts). 1. Intersection的写法: class Solution: def largestNumber(self, nums): nums = [ str(n) for n in nums] for i in range(1, len(nums)): j = i-1 while j>...
用python实现了一个版本,在构建排序的时候需要借助functools.cmp_to_key函数 class Solution: def compare(self,x,y): num1=x+y num2=y+x if(num1<num2): return 1 elif(num1>num2): return -1 return 0 def largestNumber(self, nums: List[int]) -> str: nums_=sorted(map(str,nums),key=f...
= bch: return ord(ach) - ord(bch) # 都相等,则两个字符串数字相同 return 0 # 将比较函数转换成 key cmp_key = cmp_to_key(cmp) class Solution: def kthLargestNumber(self, nums: List[str], k: int) -> str: #第 k 大就是第 n - k + 1 小 k = len(nums) - k + 1 # 按升序...
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https://leetcode-cn.com/probl... 会超时的方法: 双重循环 最简单的思路,时间复杂度 O(n^2) 会超时(最后附超时代码) 分治算法 先找到当前数组中最小元素。 那么答案将在一下三种情况中: 包含最小元素,那么高度是最小元素高度,长度是整个区间
题目地址:https://leetcode.com/problems/kth-largest-element-in-a-stream/description/ 题目描述 Design a class to find the kth largest element in a stream. Note that it is the kth largest element in the sorted order, not the kth distinct element. ...
Largest Number 二、解题 关键点就在于,如何对比两个数的大小?(理解为两个数谁应该放在前面),解法是按照顺序拼接两个字母串进行比较,如果a +b串 大于 b+a串,那么a比较大(即题意中理解的a应该放在前面),反之b比较大。 三、尝试与结果 classSolution:defsmaller(self,a,b):strA=str(a)+str(b)strB=str(...
In a given integer array nums, there is always exactly one largest element. Find whether the largest element in the array is at least twice as much as every other number in the array. If it is, return the index of the largest element, otherwise return -1. ...