原题地址: https://oj.leetcode.com/problems/largest-number/ 题目内容: Given a list of non negative integers, arrange them such that they form the largest number. For example, given[3, 30, 34, 5, 9], the largest formed number is9534330. Note: The result may be very large, so you n...
另一种方法,先把数字转化为字符串,然后通过字符串拼接去比较,这样cmp函数会好些很多 1classSolution {2public:34staticboolcmp(stringa,stringb)5{6returna+b>b+a;7}89stringlargestNumber(vector<int> &num) {1011intn=num.size();12vector<string>strNum(n);13for(inti=0;i<n;i++)14{15strNum[i]...
1classSolution {2public:3stringlargestNumber(vector<int>&nums) {4vector<string>arr;5for(intn:nums)6arr.push_back(to_string(n));7sort(arr.begin(),arr.end(),[](string&str1,string&str2){returnstr1+str2>str2+str1;});8stringres;9for(strings:arr)10res+=s;11if(res[0]=='0')12...
LeetCode: 179. Largest Number LeetCode: 179. Largest Number 题目描述 Given a list of non negative integers, arrange them such that they form the largest number. Example 1: AI检测代码解析 Input: [10,2] Output: "210" 1. 2. Example 2: AI检测代码解析 Input: [3,30,34,5,9] Output: ...
1. Description Largest Number 2. Solution 解析:这道题的关键在于想到需要编写一个比较函数来比较两个数字的“大小”,即两个数字排列的先后顺序。 Version 1 importfunctoolsclassSolution:deflargestNumber(self,nums):nums_str=[str(num)fornuminnums]nums_str=sorted(nums_str,key=functools.cmp_to_key(self....
Largest Number 二、解题 关键点就在于,如何对比两个数的大小?(理解为两个数谁应该放在前面),解法是按照顺序拼接两个字母串进行比较,如果a +b串 大于 b+a串,那么a比较大(即题意中理解的a应该放在前面),反之b比较大。 三、尝试与结果 classSolution:defsmaller(self,a,b):strA=str(a)+str(b)strB=str(...
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Leetcode-go - A simple CLI tool for searching, downloading and submitting problems to leetcode. mk - mk is a CLI tool that aims to ease contribution to any open-source project by hiding repository implementation details from the casual contributor. nbterm - Jupyter Notebooks in the terminal. ...
https://leetcode.com/problems/largest-number/discuss/53298/Python-different-solutions-(bubble-insertion-selection-merge-quick-sorts). 1. Intersection的写法: class Solution: def largestNumber(self, nums): nums = [ str(n) for n in nums] ...
In a given integer array nums, there is always exactly one largest element. Find whether the largest element in the array is at least twice as much as every other number in the array. If it is, return the index of the largest element, otherwise return -1. ...