($e instanceof HttpException)){ return response()->view('errors.custom', ['msg'=>$e->getMessage()], 500); } } }); 正常默认情况下报错的页面和上面我们截图的那个 500 错误页面非常类似,只是内容变成了 404 | NOT FOUND ,并且 http_code 也变成了 404 。如果想要自定义一个错误页面,可以直接...
Route::get('api/users/{user}/posts/{post:slug}', function (\App\User $user, \App\Post $post) { return $post; }); 那么 路由就得换成如下的方式: 代码语言:javascript 代码运行次数:0 运行 AI代码解释 http://laravel7.test/api/users/2/posts/et-saepe-enim-minus-et 这下终于可以了,终于...
return (new OfficeResource($office)) ->response() ->setStatusCode(201); } 复制代码 1. 2. 3. 4. 5. 6. 7. 8. 9. 10. 我们的 FormRequest 文件 app/Http/Requests/StoreOfficesRequest.php 包含两个规则: public function rules() { return [ 'city_id' => 'required|integer|exists:cities,...
*/publicfunctionrules(){return['name'=>'required|string','email'=>'required|email|unique:users','password'=>'required|string|min:6|max:10']; } } 运行以下命令创建一个新的 ApiController : php artisan make:controller ApiController 这将会在 app/Http/Controllers 目录下创建 ApiController.php 文...
2use Illuminate\Http\Request; 3use Illuminate\Support\Facades\Auth; 4 5/** 6 * Bootstrap any application services. 7 */ 8public function boot(): void 9{ 10 Auth::viaRequest('custom-token', function (Request $request) { 11 return User::where('token', (string) $request->token)->...
parent::__construct($message, $code, $previous);} public function getStatusCode(){ return $this...
Returning a full Response instance allows you to customize the response's HTTP status code and headers. A Response instance inherits from the Symfony\Component\HttpFoundation\Response class, which provides a variety of methods for building HTTP responses:Route::get('/home', function () { return ...
11 RateLimiter::for('global', function (Request $request) { 12 return Limit::perMinute(1000); 13 }); 14}If the incoming request exceeds the specified rate limit, a response with a 429 HTTP status code will automatically be returned by Laravel. If you would like to define your own resp...
return parent::render($request, $e); } //判断如果是MethodNotAllowedHttpException时,返回404错误 if ($e instanceof \Symfony\Component\HttpKernel\Exception\MethodNotAllowedHttpException) { return response()->json([ 'code' => '404', 'msg' => '访问地址错误', ]); } //返回 return response...
文章转发自专业的Laravel开发者社区,原始链接:https://learnku.com/laravel/t/9684/how-to-correctly-return-the-http-state-code-in-laravel 在 API 中返回状态码是很重要的,因为响应处理程序是工作在 API 的…