参考这个回答: C++: lambda-expression in unevaluated context c++11 - C++: lambda-expression in unevaluated context - Stack Overflow正在上传…重新上传取消https://stackoverflow.com/questions/52734311/c-lambda-expression-in-unevaluated-context 1.Lambda expressions are not allowed in unevaluated contexts (su...
参考这个回答: C++: lambda-expression in unevaluated context c++11 - C++: lambda-expression in unevaluated context - Stack Overflow正在上传…重新上传取消https://stackoverflow.com/questions/52734311/c-lambda-expression-in-unevaluated-context 1.Lambda expressions are not allowed in unevaluat...
For the purpose of name lookup, determining the type and value of the this pointer and for accessing non-static class members, the body of the closure type's function call operator is considered in the context of the lambda-expression. structX{intx, y;intoperator()(int);voidf(){// the...
For the purpose of name lookup, determining the type and value of the this pointer and for accessing non-static class members, the body of the closure type's operator() is considered in the context of the lambda expression. struct X { int x, y; int operator()(int); void f() { ...
expression is in an unevaluated-constext, IMO it seems there exists no reason we shall perform such instantiation (since such an id-expression possibly references to an immediate function template specialization though, the immediacy would not propagate up. I'm not sure, maybe there's an ambiguit...
expression. For example, we can take the expression(+ 1 x)and embed it anywhere we want, allowing our expression to access a binding namedxin the surrounding code. We then say that the code hascapturedour free variable. After the free variables in an expression are captured, as in the ...
: IMA_Error_StaticContext; We also have some related cases like: #31295 that are dealing withinvalid code which seems trickier to deal with. it seems like in thesecases around ActOnIdExpression and on we need some gating based on C++ Vs C but not clear where to do that. ...
for a call like `($f e)’, the passed-in expression`e’ (bound to `x’) will escape from the environment it should be evaluated if it ever needs to, namely in `env’. Indeed, `e’ may be evaluated in the body of the operative of `$f’ (in an explicit evaluation context) whi...