Can you solve this real interview question? Kth Largest Element in an Array - Given an integer array nums and an integer k, return the kth largest element in the array. Note that it is the kth largest element in the sorted order, not the kth distinct el
classSolution {//param k : description of k//param numbers : array of numbers//return: description of returnpublicintkthLargestElement(intk, ArrayList<Integer>numbers) {if(numbers ==null|| numbers.isEmpty())return-1;intresult = qSort(numbers, 0, numbers.size() - 1, k);returnresult; }...
215. Kth Largest Element in an Array 题目: Find the kth largest element in an unsorted array. Note that it is the kth largest element in the sorted order, not the kth distinct element. For example, Given[3,2,1,5,6,4]and k = 2, return 5. Note: You may assume k is always vali...
Design a class to find thekth largest element in a stream. Note that it is the kth largest element in the sorted order, not the kth distinct element. YourKthLargestclass will have a constructor which accepts an integerkand an integer arraynums, which contains initial elements from the stream...
LeetCode 215. Kth Largest Element in an Array(排序) 题目 题意:找到一个数组里第K大的数字。 题解:我们当然可以排序好了,之后,选择第K大的数字。但是这样做一点技术含量也没有。 AI检测代码解析 排序算法选用快排。寻找第K大的数字,不必把数组完全排完序之后,再找第K大。快排中是选取一个...
Find the kth largest element in an unsorted array. Note that it is the kth largest element in the sorted order, not the kth distinct element. For example, Given [3,2,1,5,6,4] and k = 2, return 5. Note: You may assume k is always valid, 1 ≤ k ≤ array's length. ...
Kth Largest Element in an Array classSolution{public:voidheapify(vector<int>&nums,intheapsize,intindex){intlargest=index;intleft=2*largest+1;intright=2*largest+2;if(nums[left]>nums[largest]&&left<heapsize){largest=left;}if(nums[right]>nums[largest]&&right<heapsize){largest=right;}if(large...
kthLargest.add(10); //返回5 kthLargest.add(9); //返回8 kthLargest.add(4); //返回8 注意:nums的长度大于等于0。 本次解题使用的开发工具是eclipse,jdk使用的版本是1.8,环境是win7 64位系统,使用Java语言编写和测试。 02 第一种解法 直接解法。使用数组,在add方法里,首先将原数组扩容,将新的元素添加...
kth_largest_element.py 源码 from typing import List # 数组中的第k大元素 class Solution: # 排序 def findKthLargest_1(self, nums: List[int], k: int) -> int: return sorted(nums)[len(nums) - k] # 使用一个堆 def findKthLargest_2(self, nums: List[int], k: int) -> int: ...
每次返回数组中的最后一个元素即可,该元素就是第k个最大的元素 代码如下: classKthLargest:def__init__(self,k:int,nums:List[int]):self.k=kiflen(nums)>=self.k:self.init_list=sorted(nums,reverse=True)[:self.k]else:self.init_list=sorted(nums,reverse=True)defadd(self,val:int)->int:index=...