int findKthLargest( int *nums, int numsSize, int k ) { PriorityQueue pQueue; pQueue = PrioQueueInit( numsSize ); int i; for( i = 0; i < numsSize; ++i ) { if( pQueue->size == k ) { if( pQueue->elements[1] < nums[i] ) { PrioQueueDelete( pQueue ); PrioQueueInsert...
Design a class to find thekthlargest element in a stream. Note that it is thekthlargest element in the sorted order, not thekthdistinct element. ImplementKthLargestclass: KthLargest(int k, int[] nums)Initializes the object with the integerkand the stream of integersnums. int add(int val)...
e.push(this.elements[i]); } return e; }; /** * @param {number[]} nums * @param {number} k * @return {number} */ var findKthLargest = function(nums, k) { var h = new BinMinHeap(k); for (var i = 0; i < k; i++) { h.insert(nums[i]); } for (; i < nums.l...
3.2 小根堆 + Counter ## LeetCode 692E - The K Frequent Word - minHeapfromtypingimportListfromheapqimportnsmallestfromcollectionsimportCounterclassSolution:deffindKthLargest(self,words:'List[str]',k:'int')->list:counter=Counter(words)## 这里 counter 的key是某个单词## 这个用了和上面一样的 Co...
Len() // 堆顶已被移动到切片最后,方便删除 x := (*h)[n-1] *h = (*h)[0 : n-1] return x } 题目链接: Top K Frequent Elements : leetcode.com/problems/t 前K 个高频元素: leetcode-cn.com/problem LeetCode 日更第 84 天,感谢阅读至此的你 欢迎点赞、收藏鼓励支持小满...
第一，绝不自己实现算法；第二，内存效率与我无关；第三，代码像屎一样漂亮。c++
FindHeaderBarSize FindTabBarSize FindBorderBarSize You haveklists of sorted integers innon-decreasing order. Find thesmallestrange that includes at least one number from each of theklists. We define the range[a, b]is smaller than range[c, d]ifb - a < d - cora < cifb - a == d -...
https://leetcode.com/problems/top-k-frequent-elements/ Given a non-empty array of integers, return the k most frequent elements. For example, Given [1,1,1,2,2,3] and k = 2, return [1,2]. Note: You may assume k is always valid, 1 ≤ k ≤ number of unique elements. ...
Design a class to find the kth largest element in a stream. Note that it is the kth largest element in the sorted order, not the kth distinct element. Your KthLargest class will have a constructor which accepts an integer k and an integer array nums, which contains initial elements from ...
1. Description Find K Closest Elements 2. Solution Version 1 classSolution:deffindClosestElements(self,arr,k,x):result=[]index=self.binarySearch(arr,x)left=index right=index+1length=len(arr)whilek:ifleft<0:result=result+[arr[right]]right+=1elifright>=length:result=[arr[left]]+result ...