CodeTestcase Test Result Test Result 1306. Jump Game III Medium Topics Companies Hint Given an array of non-negative integers arr, you are initially positioned at start index of the array. When you are at index i, you can jump to i + arr[i] or i - arr[i], check if you can ...
https://github.com/grandyang/leetcode/issues/1306 类似题目: Jump Game Jump Game II Jump Game VII 参考资料: https://leetcode.com/problems/jump-game-iii/ https://leetcode.com/problems/jump-game-iii/discuss/473221/Simple-Java-DFS-solution https://leetcode.com/problems/jump-game-iii/discuss/...
Output: true Explanation: All possible ways to reach at index 3 with value 0 are: index 5 -> index 4 -> index 1 -> index 3 index 5 -> index 6 -> index 4 -> index 1 -> index 3 Example 2: Input: arr = [4,2,3,0,3,1,2], start = 0 Output: true Explanation: One poss...
Explanation: All possible ways to reach at index 3 with value 0 are: index 5 -> index 4 -> index 1 -> index 3 index 5 -> index 6 -> index 4 -> index 1 -> index 3 Example 2: Input: arr = [4,2,3,0,3,1,2], start = 0 Output: true Explanation: One possible way to ...
Input:nums = [3,2,1,0,4]Output:falseExplanation:You will always arrive at index 3 no matter what. Its maximum jump length is 0, which makes it impossible to reach the last index. Constraints: 1 <= nums.length <= 104 0 <= nums[i] <= 105 ...
46 Leetcode 45 python Jump Game是力扣LeetCode算法刷题课程 - 基于Python3的解题思路总结的第46集视频,该合集共计99集,视频收藏或关注UP主,及时了解更多相关视频内容。
输入:nums = [2,3,1,1,4] 输出:true 解释:可以先跳 1 步,从下标 0 到达下标 1, 然后再从下标 1 跳 3 步到达最后一个下标。 示例2: 输入:nums = [3,2,1,0,4] 输出:false 解释:无论怎样,总会到达下标为 3 的位置。但该下标的最大跳跃长度是 0 , 所以永远不可能到达最后一个下标。 提示...
LeetCode 55 题,即“跳跃游戏”(Jump Game),是一道经典的贪心算法问题。题目的要求是这样的。 给定一个非负整数数组nums,你最初位于数组的第一个索引处。数组中的每个元素代表你在该位置可以跳跃的最大长度。你的目标是判断你是否能够到达最后一个索引。 详细说明: 输入:一个数组nums,其中nums[i]表示从索引i处...
LeetCode - Jump Game,一開始想DP一步步迭代更新,求出跳到最后一个的最小步数,可是时间复杂度O(nk),会超时。再一想,发现该题仅仅须要返回是否能到达最后一个,不须要最小步数,所以迭代时候仅仅须要保留当前可以走到的最远距离tmpMax,时间复杂度降到O(n)。classSoluti
递归 Java 递归判断是否到0,或者是否已经访问过 class Solution { boolean[] visited; public boolean canReach(int[] arr, int start) { int len = arr.length; visited = new boolean[len]; Arrays.fill(visited, false); visited[start] = true; return visit(arr, start); } private boolean visit(...