function findFirstCommon(head1, head2) { if (!head1 || !head2) return null // 获取链表长度 let length1 = getLength(head1); let length2 = getLength(head2); // 长链表先走 length2 - length1步 let short, long, interval; if(length1 > length2){ long = head1 short = head2 interva...
所有就验证查出。 首先实现思路就是: 1.定义一个全局数组变量:var nubList = []; 2.进入该扫描页面先查找已扫描的数据。 &nb...js some循环 找出一个数组中符合条件的另一个数组 需求效果:请求"热门兴趣"群的接口,还有一个“我参加的群”的接口,要在热门兴趣群里面标记我参加的兴趣群,如果是我参加的就...
下面是做剑指offer中,链表系列题的总结,参考答案如下: (1)输入一个链表,从尾到头打印链表每个节点的值。 思路:用一个数组来接收打印的链表,链表的结构已经给出。 /*function ListNode(x){ this.val = x; this.next = null; }*/ function printListFromTailToHead(head) { var arr=[]; while(head){ ...
https://developer.mozilla.org/en-US/docs/Web/JavaScript/Reference/Global_Objects/Array/findIndex vararray1 = [5, 12, 8, 130, 44];functionfindFirstLargeNumber(element) {returnelement > 13; } console.log(array1.findIndex(findFirstLargeNumber));//expected output: 3 js里~是位取反。反正作为逻...
- const question = await db.question.findFirst({where: {id}}) + const question = await db.question.findFirst({ + where: {id}, + include: {choices: true}, + }) if (!question) throw new NotFoundError() return question }, )
res.status(200).json({ users });break;case'POST':// createtry{const{ name, username, email,password: _password } = body;// todo: validate...const_user =awaitprisma.user.findFirst({where: { email }, });if(_user)thrownewError(`The user with email:${email}already exists.`);const...
{id:"desc"}});returnuser;}// 根据主键获取用户信息exportasyncfunctiongetUserById(id:number){constkey=`${userIdKey}${id}`;constcacahe=awaitredis.get(key);letuser:cmsUser|null=null;if(cacahe){user=JSON.parse(cacahe);}else{user=awaitprisma.cmsUser.findFirst({where:{id}});if(user){...
转到src/pages/questions/index.tsx。注意,为你生成了一个QuestionsList组件: // src/pages/questions/index.tsx exportconst QuestionsList = () => { const router = useRouter() const page = Number(router.query.page) || 0 const [{ questions, hasMore }, { isPreviousData }] = usePaginatedQuery...
Blitz.js takes a zero-API approach to connecting your Next.js front end to the back-end datastore. Here's how it works.
()//findFirst-返回第一个元素//Optional是Java8中避免空指针异常的容器类 .sorted((e1,e2)->Double.compare(e1.getSalary(), e2.getSalary())) .findFirst(); System.out.println(op.get());//Employee [name=王五, age=26, salary=3333.33, Status=VOCATION] Optional<Employee> op2=employees....