leetcode【数组】---349. Intersection of Two Arrays(两个数组的交集),程序员大本营,技术文章内容聚合第一站。
leetcode 350-Intersection of Two Arrays II 难度:easy Example: Given nums1 = [1, 2, 2, 1], nums2 = [2, 2], return [2, 2]. Note: Each element in the result should appear as many times as it shows in both arrays. ... ...
Given two arrays, write a function to compute their intersection. Example: Given nums1 = [1, 2, 2, 1], nums2 = [2, 2], return [2]. Note: 1、Each element in the result must be unique. 2、The result can be in any order. 要完成的函数: vector<int> intersection(vector<int>& ...
LeetCode 349. Intersection of Two Arrays 题目Given two arrays, write a function to compute their intersection. Note: Each element in the result must be unique. The result can be in any order. 解析 求两个数组的交集,如果用java中的set来实现的话,此题就没有什么难度。但是用C语言的话还是.....
今天介绍的是LeetCode算法题中Easy级别的第75题(顺位题号是349)。给定两个数组,编写一个函数来计算它们的交集。例如: 输入:nums1 = [1,2,2,1],nums2 = [2,2] 输出:[2] 输入:nums1 = [4,9,5],nums2 = [9,4,9,8,4] 输出:[9,4] ...
LeetCode题解之 Intersection of Two Arrays 1、题目描述 2、问题分析 借助于set来做。 3、代码 1 class Solution { 2 public: 3 vector<int> intersection(vector<int>& nums1, vector<int>& nums2) { 4 vector<int> res; 5 set<int> s1; 6 set<int> s2; 7 for( auto & n : nums1) 8 s1...
Can you solve this real interview question? Intersection of Two Arrays - Given two integer arrays nums1 and nums2, return an array of their intersection. Each element in the result must be unique and you may return the result in any order. Example 1:
Given two arrays, write a function to compute their intersection. Example: Givennums1=[1, 2, 2, 1],nums2=[2, 2], return[2]. Note: Each element in the result must be unique. The result can be in any order. 两种思路,一种是map,一种是排序归并的思想: ...
两个数组的交集 II Intersection of Two Arrays II 难度:Easy| 简单 相关知识点:排序 哈希表 双指针 二分查找题目链接:https://leetcode-cn.com/problems/intersection-of-two-arrays-ii/ 官方题解:https://leetcode-cn.com/problems/intersection-of-two-arrays-ii/solution/...
Leetcode 350:Intersection of Two Arrays II Given two arrays, write a function to compute their intersection. 说人话: 求两个数组的交集。 举例1: 举例2: [法1] Map 记录频次 思路 因为是求交集,所以元素出现的次数是需要进行考虑了。这里笔者考虑到用 Map 这个集合框架来解决这个问题,主要是基于 key-...