sinxdx=−dt Step 2: Rewrite the IntegralNow, we can rewrite the integral ∫sinxsin(cosx)dx using our substitution:∫sinxsin(cosx)dx=∫sinxsin(t)dxSubstituting for sinxdx:=∫sin(t)(−dt)=−∫sin(t)dt Step 3: IntegrateNow we can integrate −∫sin(t)dt:−∫sin(t)dt=−(...
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Integrate: \int cosxe^{sinx} dx Integrate: \int(ln x + l) \sqrt {(x \cdot ln x)^2 + 1} dx Integrate: \int \frac{3x}{4+x^2} dx Integrate: \int 3x^2\sqrt{x^3 + 1} dx Integrate: \int_0^{0.6} \frac{x^2}{\sqrt{9 - 25x^2 dx ...
Integrate: integral_0^pi/2 (sinx + cosx)^2 Integrate 1/sinx Integrate the function: sin(x) sin(cos x) Integrate the function: 2 cos x - 3 sin x/6 cos x + 4 sin x Integrate the function: e^x (1 + sin x/1 + cos x) Integrate the function: sin y/1 + cos y Integrate ...
Let u = sinx. Then du = cos x dx.The integral becomes:du/ (u^2 + 9)Next, 9 is factored out of the denominator:1/9 integeral du / ( (1/3u)^2 + 1)This is merely the derivative of the arctan function arctan(z) where z = 1/3u...
Integrate \frac {sinx}{(sinx+cosx)} dx Determine the indefinite integral below. \int \frac {dx}{x^9}\ \int \frac {dx}{x^9}=\Box Integrate the following. a. \int \frac {2x + 2}{x^2 + 2x + 5} dx b. \int \sin^3 x \cos x dx c. \int \frac {(\ln(x + 2))^...
Integrate : int log(sinx).cosx dx 03:11 সমাকল করো:inte^x(cosx-sinx)dx 01:26 সমাকল করো:int(dx)/(sinx+cosx) 02:00 সমাকল করো:int(1+sinx)/(sinx (1+cosx))dx 04:40 Find the following integral: int(sinx+cosx)dx 01...
Answer to: Integrate (a) \int sinxdx (b) \int sin^{2}xdx (c) \int sinxcosxdx (d) \int sin^{3}dx By signing up, you'll get thousands of step-by-step...
Integrate: \int cosxe^{sinx} dx Integrate: integral_1^7(ln(x)^2)/(x^3) dx Integrate: \int \frac{2x}{\sqrt{x^2 +2 dx Integrate. 1. \int\limits^{2 \pi}_0 \cos t dt 2. \int\limits^{10}_5 3 dx 3. \int\limits^e_1 \frac {1}{x} dx integrate \ 4 \ to \ 0 ...
2cosx−3sinx=−12(−3sinx+2cosx) Thus, we can replace the numerator: I=∫−12dtt 5. Integrate: The integral simplifies to: I=−12∫1tdt=−12ln|t|+C 6. Substitute Back: Substitute back t=3cosx+2sinx: I=−12ln|3cosx+2sinx|+C Final Answer:I=−12ln|3cosx+2sinx|...