sinxdx=−dt Step 2: Rewrite the IntegralNow, we can rewrite the integral ∫sinxsin(cosx)dx using our substitution:∫sinxsin(cosx)dx=∫sinxsin(t)dxSubstituting for sinxdx:=∫sin(t)(−dt)=−∫sin(t)dt Step 3: IntegrateNow we can integrate −∫sin(t)dt:−∫sin(t)dt=−(...
Answer to: Integrate (a) \int sinxdx (b) \int sin^{2}xdx (c) \int sinxcosxdx (d) \int sin^{3}dx By signing up, you'll get thousands of step-by-step...
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Integrate: \int cosxe^{sinx} dx Integrate: \int(ln x + l) \sqrt {(x \cdot ln x)^2 + 1} dx Integrate: \int \frac{3x}{4+x^2} dx Integrate: \int 3x^2\sqrt{x^3 + 1} dx Integrate: \int_0^{0.6} \frac{x^2}{\sqrt{9 - 25x^2 dx ...
Integrate: integral_0^pi/2 (sinx + cosx)^2 Integrate 1/sinx cos 5x sin 3x. Integrate with respect to x. Integrate the following using integration by parts integral x 2 sin 5 x d x Integrate a) \int x^2 \sin {(2x)} dx b) \int \sqrt {2 + \cos {(3x) \sin {(3x)} dx ...
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Integrate: integral_0^pi/2 (sinx + cosx)^2 Integrate 1/sinx Evaluate the indefinite integral of sin(x) cos(x) dx using integration by parts How to integrate sqrt(1 - cos(x)) Integrate the given function. integral 5 sin^2 x dx ...
Integrate : int log(sinx).cosx dx 03:11 সমাকল করো:inte^x(cosx-sinx)dx 01:26 সমাকল করো:int(dx)/(sinx+cosx) 02:00 সমাকল করো:int(1+sinx)/(sinx (1+cosx))dx 04:40 Find the following integral: int(sinx+cosx)dx 01...
Integrate: \int cosxe^{sinx} dx Integrate : \int_1^{\infty}25 e^{-\sqrt{ x / \sqrt{x} dx. Integrate: \int \frac {(\sqrt x - 1)^2}{\sqrt x} dx Integrate. \int 16x(8x^2 + 7)^6 dx Integrate from (\frac {-ln(2)}{11}) to 0 of cosh^2 (\frac {11x}{2}) dx...
Integrate the functions e^(x)((1+sinx)/(1+cosx)) 06:05 Integrate the following functions : e^(x)((1+xlogx)/(x)) 00:55 int(logx+(1)/(x^(2)))e^(x)dx=...+c 03:21 int(x^(6)+7x^(5)+6x^(4)+5x^(3)+4x^(2)+3x+1)e^(x)dx=...+c 02:47 intxcos2xdx=......