(sin xcos x)((cos ^2x+2sin ^2x)) 相关知识点: 试题来源: 解析 12log _e(cos ^2x+2sin ^2x) 结果一 题目 Integrate the following functions with respect to x: 答案相关推荐 1Integrate the following functions with respect to x: 反馈...
Integrate {eq}\displaystyle \int \cos x \sin x \ \sqrt {1 - \sin^4 x \ } \ dx. {/eq} Integration using Substitution and Reduction Formula: When conventional methods are finding it difficult to solve the integral problem, then substitution method comes to the rescue. Here we ...
{eq}\, \, cos5x\, \, sin9x \, \, dx {/eq} Indefinite Integral: You have to find the given indefinite integral. We can use multiplication formula of sine and cosine function {eq}\sin x\cos y = \frac{1}{2}\left[ {\sin \left( {x + y} \right) - \sin \left( {y - x...
Integrate the functions sin(a x+b)cos(a x+b) 02:23 Integrate the functionsxsqrt(1+2x^2) 02:56 Integrate the functions(4x+2)sqrt(x^2+x+1) 03:12 int(dx)/(sin^2xcos^2x)equals(A) tanx+cotx+C (B) tanx-cotx+C(C) tanxco... 02:58 int(10 x^9+10 x^x(log)(e^(10))dx...
Integrate[Sin[x],x] Integrate[Cos[x],x] 运行这些代码,我们可以得到sin(x)和cos(x)的不定积分的一般形式。 3.求解多重积分 除了求解一维函数的不定积分外,Integrate函数还可以用于求解多维函数的不定积分。例如,我们可以求解二维函数的不定积分,代码如下: Integrate[x^2+y^2,x,y] 其中,x和y是自变量。
f(n):=expand(integrate(x*(n+cos(x/2)),x)-integrate(n*x,x)); are same function but... When n are even numbers, results are always 1/2(%i2) f(1); (%o2) 2*x*sin(x/2)+4*cos(x/2) (%i3) f(2); (%o3) x*sin(x/2)+2*cos(x/2) (%i4) f(3);(%o4) 2*x*sin...
This is incorrect since cos(x) >= 0 over the integration range, so the integrand is always real. The actual value of the integral is -%pi*log(2)/2, which we have. The imaginary part should not be there. Tracing antideriv indicates that Maxima is computing the antiderivative and computi...
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这是同一被积函数的两种不同分解. 缺省时,Sin[x] 和Cos[x] 项均被包括在内:In[19]:=Out[19]=在设置为 "AdditiveTerm"->Sin[x] 时,Sin[x] 项不被包括在检测到的内核中:In[20]:=Out[20]=我们可以看到如何使用 "LevinFunctions" 选项将函数组包括在被积函数中或从被积函数中排除....
这是同一被积函数的两种不同分解. 缺省时,Sin[x] 和Cos[x] 项均被包括在内:In[19]:=Out[19]=在设置为 "AdditiveTerm"->Sin[x] 时,Sin[x] 项不被包括在检测到的内核中:In[20]:=Out[20]=我们可以看到如何使用 "LevinFunctions" 选项将函数组包括在被积函数中或从被积函数中排除....