2elpha2 第一个注意到分母可以变成【3+cos(2x)】/2而正好sin(2x)dx=-dcos(2x)/2题目就转化为-∫dcos(2x)/【3+cos(2x)】 2022-01-23 12:134回复 晓之车高山老师 其实up表达的意思就是,被积函数某个地方稍有改动,对应不定积分表达式就可能有很大的变化,甚至完全不同 2022-01-24 03:072回复 QNのstar...
数字帝国:integral-calculator。第十四题∫xsinxcosxdx。没有疫苗就不打针算是祸国殃民吗?唉。第十五题∫(x²)cos²(x/2)dx。∫xln(x-1)dx。∫(x^2-1)sin2xdx。∫(lnx)³/x²dx。 知识分享官 必剪创作 知识 科学科普 高考加油 高等数学高数微积分calculus 湖南省益阳市桃江县松木塘镇关山口...
Evaluate the integral. integral (sin x + sin x cos x) dx. Evaluate the integral. integral (2 sin (2 x) + sec^2 (x)) dx Evaluate the integral. integral 2 sin (2 y - 1) dy Evaluate the integral: integral ({4 sin x cos x} / {sin 2x cos 2x}) dx. ...
(a) \int_{0}^{1} (3x^3-5) cosx dx (b) \int_{0}^{e-1} ln(x+1) dx Evaluate the indefinite integral. Integral of (cos x)/(sin^2 x) dx. Evaluate the indefinite integral. (Use C for the constant of integration.) Integral of (sin 2x)/(1 + cos...
integral 1/-e^{-x} + e^x dx Evaluate the integral: integral ln (x^2) / x dx. Evaluate the integral: integral from 3 to 0 of (2z - 3) dz. Evaluate the integral. Integral 6 sin^5(2x) cos (2x) dx Evaluate the integral. Integral from -3 to 3 of xe^(-x^2 + 2) dx...
∫cotxdx The {MathJax fullWidth='false' dxTrigonometry Functions There are six trigonometric functions. Their names and abbreviations are as follows: Sine (sin) Cosine (cos) Tangent (tan) Secant (sec) Cosecant (cos) Cotangent (cot) Trigonometric functions are used to find ratios between the...
∫ sin x dx = – cos x + C ∫ cos x dx = sin x + C ∫ sec2x dx = tan x + C ∫ csc2x dx = -cot x + C ∫ sec x (tan x) dx = sec x + C ∫ csc x ( cot x) dx = – csc x + C ∫ (1/x) dx = ln |x| + C ...
int (sec^(2)x)/(sqrt(a+b tan x))dx= 02:13 int (log (tanx))/(sin x cos x)dx= 02:10 int([x+sqrt(a^(2)+x^(2))]^(n))/sqrt(a^(2)+x^(2))dx(n ne0)= 03:17 If int (sin 2x-cos 2x) dx=(1)/(sqrt(2)) sin (2x-a)+c then a= 04:46Exams...
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Find the following integral: {eq}\int \frac{\cos 2x}{\sin^3 2x} \, \mathrm{d}x {/eq}. Integration in Calculus: Integration is one of the main concepts in Calculus. Integration techniques can be used to find antiderivatives of a trigonometric function. To solve this problem,...