Evaluate the integral \int [0.3-0.8] cosx-ln(9sinx)dx Evaluate the integral. (Use C for the constant of integration.) integral of (x^2 + 6 x) cos x dx Evaluate the integral: 0 pi sin(x) e cos(x) dx Evaluate the integral. \int_{0}^{5}3e^x+4 \cos...
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What is the integral of cosx^3 sinx^8 dx [write cosx^3 as cosx(1-sinx^2)] Find the indefinite integral S(x - 6x^{14} + \frac {1}{8x}) dx Find the indefinite integral: int (x-5x^4 + 1/2x) dx Find the indefinite integral: 1/x ln(x^3) dx Find the indefinite integral:...
Evaluate: int((2x+1))/((x^(2)+4x+1)^(3//2))dx 04:03 If int((2x+3)dx)/(x(x+1)(x+2)(x+3)+1)=C-(1)/(f(x)) where f(x) is of th... 04:17 The integral intsqrt(cotx)e^(sqrt(sinx))sqrt(cosx)dx equals 01:52 Evaluate :int(dx)/(xsqrt(x^(6)+1)) equals...
Evaluate the integral \int [0.3-0.8] cosx-ln(9sinx)dx Evaluate the integral. integral_0^{pi / 2} {x cos x - sin x} / {x^2} dx Find the integral integral x^3 sin x dx Solve the integral. \int \frac{\sin y\ dy}{\sqrt{1} + \cos y} ...
求不定积分Integral of (a*sinx + b*cosx)/(c*sinx + d*cosx) dx(sinx)'=cosx (cosx)'=-sinx,在导数里,是2个非常友好的函数,本题的分子分母结构一样,只是系数不同,可以利用这个条件,用待定系数的方法,将被积函数分解成2个容易积分的函数,求解出答案。, 视频播放量
Find the number of integral values of k for which the equation 12cosx - 5 sinx = 2k+1 has a solution. View Solution Find ∫dxsinx+cosx View Solution The least value of a for which the equation 4sinx+11−sinx=a has at least one solution on the interval (0,π2) is View Solut...
百度试题 结果1 题目Evaluate the integral using the properties of even and odd functions as an aid.∫_(-∞)^(+∞)sinxcosxdx 相关知识点: 试题来源: 解析 0 反馈 收藏
对积分Ι=integral from n=0 to +∞((sinx/x)dx)=π/2的计算方法进行深入研究,从多种渠道得出这一结果,值得注意的是本文应用了Fourier积分变换的对偶性质,巧妙而不失优美地给出了一个新方法,同时还得到一个新的收敛积分:integral from n=0 to +∞((sinx/x)~2dx)=π/2.关键...
Evaluate the definite integral from 0 to pi/4 of (4cosx+7sinx). Evaluate the following definite integrals: a) the integral from -1 to 0 of (5x +(3)(e^x))dx b) the integral from 1 to 2 of (1y - 5(y^7))/(y^3) dy c) the integral from 0 to pi/4 of (-4 - ...