Evaluate the integral: integral from 2 to infinity of 1/(x^3) dx. Evaluate the integral: integral from 1 to infinity of 1/(2x + 1)^3 dx. Evaluate the integral: integral from 0 to infinity of 1/(1 + x^2) dx. Evaluate the integral: integral from 0 to infinity of 1/(2x ...
Determine if the improper integral converges or diverges. Integral from 0 to infinity of 8xe^(-x^2) dx. Determine if the improper integral \int_{-\infty}^{0} xe^x \,dx converges or diverges. If it converges, then determine its value. ...
The integral I (sub l,l')(k,k') = Integral from 0 to infinity (j sub l)(kr)(j sub l')(k'r)r squared dr, in which the spherical Bessel functions (j sub l)(kr) are the radial eigenfunctions of the three-dimensional wave equation in spherical coordinates, is evaluated in terms...
Find the integral: Integral from 0 to infinity of (sqrt(1 + e^(-x)) - 1) dx. Evaluate the following integral. integral {e^x - 1} / {e^{2 x} + 1} dx Evaluate the integral. Integral of e^x cos x dx. Evaluate the integral: Integral 1/1-...
A RIDICULOUSLY AWESOME INTEGRAL int sin(x)sinh(x) from 0 to infinity 485 1 12:33 App int 0 to 1 (xln(x))((x+1)(x^2+1)) & a cool related integral 1763 1 25:33 App 积分学中最难的问题之一:Coxeter积分 148 0 12:58 App Ramanujan's integral is ridiculous!【Ramanujan的积分太可...
93 0 A result you definitely should know【一个你绝对应该知道的结果】 蛋之蛋 174 1 1/(1+x^s)^s从0到无穷大的一个有趣的广义积分 蛋之蛋 830 0 A RIDICULOUSLY AWESOME INTEGRAL int sin(x)sinh(x) from 0 to infinity 蛋之蛋 100 0 这课讲得真大 啊不是 这板书真白 又见初夏- 581...
Evaluate the integral: integral_{0}^{1} e^x square root {e^{2x} - 1) dx. Compute the following integral: integral from 1 to infinity of e^(-2x) dx. Compute the following indefinite integral. Show all work. Integral of e^(2x) sin x dx. ...
These symmetries are applied to decouple the Dirac equation for a charged particle interacting wi... VP Maslov - 《Mathematical Notes》 被引量: 6发表: 1994年 Evaluation of [1 over the square root of 2 pi integral from 0 to infinity du u to the n-2 times e to the negative 1/2 (u...
where [[bar.[gamma]].sub.bm] = [P.sub.b]/[[sigma].sup.2.sub.m] and [E.sub.1] (x) = [[integral].sup.[infinity].sub.x]([e.sup.-t]/t)dt is the exponential integral function. On the multiuser diversity of relay-aided downlink systems using reduced feedback ...
Evaluate the integral: integral from 1 to infinity of 1/(2x + 1)^3 dx. Evaluate the integral: integral from 0 to infinity of 1/(2x + 3)^4 dx. Evaluate the integral: integral from 0 to infinity of 1/(1 + x^2) dx. Evaluate the integral: integral from -infinity to 0 of...