importjava.util.Stack; /* * Java Program to traverse a binary tree * using inorder traversal without recursion. * In InOrder traversal first left node is visited, followed by root * and right node. * * input: * 4 * / \ * 2 5 * / \ \ * 1 3 6 * * output: 1 2 3 4 5 ...
classSolution(object):definorderTraversal(self, root):#递归""":type root: TreeNode :rtype: List[int]"""ifnotroot:return[]returnself.inorderTraversal(root.left) + [root.val] + self.inorderTraversal(root.right) Java解法 classSolution {publicList < Integer >inorderTraversal(TreeNode root) ...
definorderTraversal(self, root): res=[] ifroot: res=self.inorderTraversal(root.left) res.append(root.val) res=res+self.inorderTraversal(root.right) returnres Python: Recursion, briefly done 1 2 3 classSolution(object): definorderTraversal(self, root): return(self.inorderTraversal(root.lef...
That's all for now onhow you can implement theinOrdertraversal of a binary tree in Java using recursion. You can see the code is pretty much similar to thepreOrdertraversal with the only difference in the order we recursive call the method. In this case, we callinOrder(node.left)first ...
Reverse inorder traversal of the above tree is: 10 9 8 7 6 5 4 3 2 1 0 C++ implementation: #include <bits/stdc++.h>usingnamespacestd;classTreeNode{// tree node is definedpublic:intval; TreeNode*left; TreeNode*right; TreeNode(intdata) ...
inorder traversal of a binary tree in Java, in thefirst part, I have shown you how to solve this problem using recursion and in this part, we'll implement the inorder traversal algorithm without recursion. Now, some of you might argue, why use iteration if the recursive solution is so ...
usingnamespacestd; // Data structure to store a binary tree node structNode { intdata; Node*left,*right; Node(intdata,Node*left,Node*right) { this->data=data; this->left=left; this->right=right; } }; // Utility function to perform preorder traversal on a given binary tree ...
import java.util.Stack;/* * Java Program to traverse a binary tree * using inorder traversal without recursion. * In InOrder traversal first left node is visited, followed by root * and right node. * * input: * 4 * / \ * 2 5 ...
http://www.geeksforgeeks.org/inorder-tree-traversal-without-recursion/ 1 #include 2 #include 3 #include 4 #include 5 #include 6 using namespace std; 7