Given a binary tree, return theinordertraversal of its nodes' values. For example: Given binary tree{1,#,2,3}, 1 \ 2 / 3 return[1,3,2]. Note:Recursive solution is trivial, could you do it iteratively? 题解: 中序遍历:递归左 处理当前 递归右。 画图的话就是,之前离散老师教的,从ro...
classSolution { public List<Integer>inorderTraversal(TreeNode root) { List<Integer> traversal = new ArrayList<>(); forInOrderTraversal(root,traversal); returntraversal; } public static void forInOrderTraversal(TreeNode T,List<Integer>traversal){ if(T==null) return; forInOrderTraversal(T.left,...
核心的思路就是先递归左侧子节点,之后读取中间节点的值,再递归右侧子节点。 public List<Integer> inorderTraversal(TreeNode root) { List<Integer> result = new ArrayList<Integer>(); inorderTraversal(root, result); return result; } public void inorderTraversal(TreeNode root, List<Integer> result){ ...
importjava.util.ArrayList;importjava.util.List;// 定义二叉树节点类classTreeNode{int val;TreeNode left;TreeNode right;TreeNode(int x){val=x;}}// 二叉树工具类publicclassBinaryTreeTraversal{// 中序遍历二叉树publicList<Integer>inorderTraversal(TreeNode root){List<Integer>result=newArrayList<>();i...
题目: Given preorder and inorder traversal of a tree, construct the binary tree. Note: You may assume that duplicates do not exist in the tree. 根据前序遍历和中序遍历结果构造二叉树。 思路分析: 分析二叉树前序遍历和中序遍历的结果我们发现: 二叉树前序遍历的第一个节点是根节点。 在中序遍历...
094.binary-tree-inorder-traversal Given a binary tree, return the inorder traversal of its nodes' values. For example: Given binary tree [1,null,2,3], 1 \ 2 / 3 return [1,3,2]. Note: Recursive solution is trivial, could you do it iteratively?
2、使用递归思想解决。 /** * Definition for a binary tree node. * public class TreeNode { * int val; * TreeNode left; * TreeNode right; * TreeNode(int x) { val = x; } * } */ class Solution { public List<Integer> inorderTraversal(TreeNode root) { ...
Given preorder and inorder traversal of a tree, construct the binary tree. Note: You may assume that duplicates do not exist in the tree. 翻译:给定树的前序和中序遍历,构造二叉树。 注意: 树中不存在重复项。 思路:首先,你应该知道 前序遍历:根节点,左子树,右子树; ...
This is how the code for In-order Traversal looks like: Example Python: definOrderTraversal(node):ifnodeisNone:returninOrderTraversal(node.left)print(node.data,end=", ")inOrderTraversal(node.right) Run Example » TheinOrderTraversal()function keeps calling itself with the current left child...
简介:题目:给定一个二叉树,返回它的中序 遍历。Given a binary tree, return the inorder traversal of its nodes' values.示例:输入: [1,null,2,3] 1 \ 2 / 3输出:... 题目: 给定一个二叉树,返回它的中序遍历。 Given a binary tree, return theinordertraversal of its nodes' values. ...