叫 Morris Traversal,在介绍这种方法之前,先来引入一种新型树,叫Threaded binary tree,这个还不太好翻译,第一眼看上去以为是叫线程二叉树,但是感觉好像又跟线程没啥关系,后来看到网上有人翻译为螺纹二叉树,但博主认为这翻译也不太敢直视,很容易让人联想到为计划生育做出突出贡献的某世界...
classSolution(object):definorderTraversal(self, root):#递归""":type root: TreeNode :rtype: List[int]"""ifnotroot:return[]returnself.inorderTraversal(root.left) + [root.val] + self.inorderTraversal(root.right) Java解法 classSolution {publicList < Integer >inorderTraversal(TreeNode root) ...
1. Problem Descriptions:Given two integer arrays inorderandpostorderwhereinorderis the inorder traversal of a binary tree andpostorderis the postorder traversal of the same tree, construct and retu…
Given preorder and inorder traversal of a tree, construct the binary tree. Note: You may assume that duplicates do not exist in the tree. For example, given preorder = [3,9,20,15,7] inorder = [9,3,15,20,7] Return the following binary tre...
Given preorder and inorder traversal of a tree, construct the binary tree. Note: You may assume that duplicates do not exist in the tree. 本题难度Medium。 二分法 【复杂度】 时间O(N) 空间 O(N) 【思路】 我们先考察先序遍历序列和中序遍历序列的特点。对于先序遍历序列,根在最前面,后面部分存...
94. 二叉树的中序遍历 - 给定一个二叉树的根节点 root ,返回 它的 中序 遍历 。 示例 1: [https://assets.leetcode.com/uploads/2020/09/15/inorder_1.jpg] 输入:root = [1,null,2,3] 输出:[1,3,2] 示例 2: 输入:root = [] 输出:[] 示例 3: 输入:ro
名字叫做, morrois traversal, 自己写了下: My code: /** * Definition for a binary tree node. * public class TreeNode { * int val; * TreeNode left; * TreeNode right; * TreeNode(int x) { val = x; } * } */publicclassSolution{publicList<Integer>inorderTraversal(TreeNoderoot){List...
链接:https://leetcode.com/problems/construct-binary-tree-from-preorder-and-inorder-traversal/description/ 难度:Medium 题目:105. Construct Binary Tree from Preorder and Inorder Traversal Given preorder and inorder traversal of a tree, construct the binary tree. ...
题目: Given preorder and inorder traversal of a tree, construct the binary tree. Note: You may assume that duplicates do not exist in the tree. 根据前序遍历和中序遍历结果构造二叉树。 思路分析: 分析二叉树前序遍历和中序遍历的结果我们发现: 二叉树前序遍历的第一个节点是根节点。 在中序遍历...
I am a fighter 来自专栏 · leetcode每日斩 题目 Given a binary tree, return the inorder traversal of its nodes' values. For example: Given binary tree [1,null,2,3], return [1,3,2]. Note: Recursive solution is trivial, could you do it iteratively? 解析 嘻嘻,最近因为马上要面试,就回...