题目Given a binary tree, return the inorder traversal of its nodes' values. For example: Given binary tree [1,null,2,3], return [1,3,2]. Note: Recursive solution is trivial, could you do it iter…
* TreeNode(int x) : val(x), left(NULL), right(NULL) {} * };*/classSolution {public: vector<int> inorderTraversal(TreeNode*root) { vector<int>ret;if( !root )returnret; stack<TreeNode*>sta; sta.push(root);while( !sta.empty() ) { TreeNode*tmp =sta.top(); sta.pop();if(...
traversal(rst, root.right); } } 2. Iterator 1. Create a node to present current node. 2. If current node is not null and stack is not empty 1) keep adding all the left child to the stack. 2) move the current node to the top of the stack 3) pop the top node and add it to...
1. Problem Descriptions:Given two integer arrays inorderandpostorderwhereinorderis the inorder traversal of a binary tree andpostorderis the postorder traversal of the same tree, construct and retu…
94. Binary Tree Inorder Traversal 题目描述 Given a binary tree, return theinorder For example: Given binary tree [1,null,2,3], 1 \ 2 / 3 return [1,3,2]. Note: 思路 本题的目的是将一个二叉树结构进行中序遍历输出...
Given a binary tree, return the inorder traversal of its nodes’ values. For example: Given binary tree [1,null,2,3], \ 1. return [1,3,2]. Note: Recursive solution is trivial, could you do it iteratively? 思路: 1、题意为中序遍历二叉树。遍历顺序为左—>根—>右。
Given preorder and inorder traversal of a tree, construct the binary tree. Note: You may assume that duplicates do not exist in the tree. 翻译:给定树的前序和中序遍历,构造二叉树。 注意: 树中不存在重复项。 思路:首先,你应该知道 前序遍历:根节点,左子树,右子树; ...
Binary Tree Level Order Traversal 二叉树层序遍历 Example Givenbinary tree[3,9,20,null,null,15,7],3/\920/\157returnits level order traversalas:[[3],[9,20],[15,7]] BFS方法 var levelOrder=function(root){if(!root)return[]conststack=[root]constres=[]while(stack.length){constlen=stack...
Binary tree traversal: Preorder, Inorder, and Postorder In order to illustrate few of the binary tree traversals, let us consider the below binary tree: Preorder traversal: To traverse a binary tree in Preorder, following operations are carried-out (i) Visit the root, (ii) Traverse the le...
Given a binary tree, return the inorder traversal of its nodes' values. For example: Given binary tree [1,null,2,3], 1 \ 2 / 3 return [1,3,2]. Note: Recursive solution is trivial, could you do it iteratively? 中序遍历树,并将遍历结果添加到数组中。分别用递归和循环的方式结局。