* int val; * TreeNode *left; * TreeNode *right; * TreeNode(int x) : val(x), left(NULL), right(NULL) {} * };*/classSolution {public: vector<int> inorderTraversal(TreeNode*root) { vector<int>result; helper(root, result);returnresult; }private:voidhelper(TreeNode *root, vector<...
* @param root: A Tree * @return: Inorder in ArrayList which contains node values. */vector<int>inorderTraversal(TreeNode * root){// write your code herevector<int> result; traverse(root, result);returnresult; }// 遍历法的递归函数,没有返回值,函数参数result贯穿整个递归过程用来记录遍历的结...
publicList<Integer>inorderTraversal3(TreeNoderoot){List<Integer>ans=newArrayList<>();TreeNodecur=root;while(cur!=null){//情况 1if(cur.left==null){ans.add(cur.val);cur=cur.right;}else{//找左子树最右边的节点TreeNodepre=cur.left;while(pre.right!=null&&pre.right!=cur){pre=pre.right;}...
题目描述 Given a binary tree, return the inorder traversal of its nodes' values. 主要思路: 1.递归 保持左根右的顺序即可 代码: definorderTraversal(self,root):""" :type root: TreeNode :rtype: List[int] """ifroot==None:return[]left=self.inorderTraversal(root.left)right=self.inorderTrav...
* TreeNode right; * TreeNode(int x) { val = x; } * } */classSolution{public List<Integer>inorderTraversal(TreeNode root){List<Integer>result=newLinkedList<>();TreeNode current=root;TreeNode prev=null;while(current!=null){// left firstif(current.left==null){result.add(current.val);...
* TreeNode(int x) : val(x), left(NULL), right(NULL) {} * }; */ class Solution { public: /*递归版 vector<int> inorderTraversal(TreeNode *root) { vector<int> res; solve(root,res); return res; } void solve(TreeNode *root,vector<int> &res) ...
Binary Tree Inorder Traversal Given a binary tree, return theinordertraversal of its nodes' values. For example: Given binary tree{1,#,2,3}, 1 \ 2 / 3 1. 2. 3. 4. 5. return[1,3,2]. Note: Recursive solution is trivial, could you do it iteratively?
Binary search tree traversal in order, postorder, and preorder traversal. Top of the tree, the height of the tree inorder-traversalpreorder-traversalpostorder-traversaltop-view-binary-treeheight-of-tree UpdatedSep 2, 2020 Python jaydattpatel/Binary-Tree ...
The function returns the root of the constructed binary tree. 4. Time & Space Complexity Analysis: 4.1 Time Complexity: 4.1.1 Lists as parameters In each recursive call, theindex()function is used to find the index of the root value in the inorder traversal list. This function has a time...
Morris Traversal is a method based on the idea of a threaded binary tree and can be used to traverse a tree without using recursion or stack. Morris traversal involves: Step 1:Creating links to inorder successors Step 2:Printing the information using the created links (the tree is altered ...