binary-tree-inorder-traversal /** * * @author gentleKay * Given a binary tree, return the inorder traversal of its nodes' values. * For example: * Given binary tree{1,#,2,3}, 1 \ 2 / 3 * return[1,3,2]. * Note: Recursive solution is trivial, could you do it iteratively?
和上面要求一样,只是要返回以中序方式序列的元素,这次用递归实现: 1/**2* Definition for binary tree3* struct TreeNode {4* int val;5* TreeNode *left;6* TreeNode *right;7* TreeNode(int x) : val(x), left(NULL), right(NULL) {}8* };9*/10classSolution {11public:12vector<int> pre...
The number of nodes in the tree is in the range [0, 100]. -100 <= Node.val <= 100 英文版地址 leetcode.com/problems/b 中文版描述 给定一个二叉树的根节点 root ,返回 它的中序 遍历。 示例1: 输入:root = [1,null,2,3] 输出:[1,3,2] 示例2: 输入:root = [] 输出:[] 示例3:...
binary a. 1.【计算机,数学】二进制的 2.【术语】仅基于两个数字的,二元的,由两部分组成的 tree n. 树,木料,树状物 vt. 赶上树 Tree 树状结构使计算机知道如何执行的机器指令。 in tree 【计】 入树 binary decimal 二-十进制的 binary multiplier 二进乘法器 decimal to binary 十翻二 decimal...
94. Binary Tree Inorder Traversal 题目描述 Given a binary tree, return theinorder For example: Given binary tree [1,null,2,3], 1 \ 2 / 3 return [1,3,2]. Note: 思路 本题的目的是将一个二叉树结构进行中序遍历输出...
public List<Integer> inorderTraversal(TreeNode root) { List<Integer> ans = new ArrayList<>(); getAns(root, ans); return ans; } private void getAns(TreeNode node, List<Integer> ans) { if (node == null) { return; } getAns(node.left, ans); ans.add(node.val); getAns(node.right...
Given a binary tree, return theinordertraversal of its nodes' values. For example: Given binary tree{1,#,2,3}, 1 \ 2 / 3 1. 2. 3. 4. 5. return[1,3,2]. 1 /** 2 * Definition for binary tree 3 * struct TreeNode { ...
18 A and B are two nodes on a binary tree. In the in-order traversal, the condition for A before B is ( ). A. A is to the left of B B. A is to the right of B C. A is the ancestor of B D. A is a descendant of B ...
* Definition for a binary tree node. * public class TreeNode { * int val; * TreeNode left; * TreeNode right; * TreeNode(int x) { val = x; } * } */classSolution{public List<Integer>postorderTraversal(TreeNode root){Deque<Integer>result=newLinkedList<>();if(root==null){returnnewA...
inorder 遍历 tree 基本没难度,然后还算是 Medium... 傻逼。。。 主要考的还是非递归遍历。 代码如下: ** 总结: inorder tree ** Anyway, Good luck, Richardo! My code: /** * Definition for a binary tree node. * public class TreeNode { *...