以下是实现这个功能的Python代码: def infix_to_postfix(expression): stack = [] for char in expression: if char.isdigit(): stack.append(char) elif char == '(': stack.append(char) elif char == ')': while stack[-1] != '(': stack.pop() stack.pop() else: while stack and stack[...
postfix[index] =stack.Pop(); index++; } returnpostfix.TakeWhile(item => item != null).ToArray(); } 看答案 如果你替换array由A.Stack<string>,你不必跟踪你在哪里index多变的。 然后,您可以返回结果postfixStack.ToArray() 我的实施方式: publicstaticstring[] InfixToPostfix(string[] infixArray ) ...
1. What is the primary purpose of converting infix expressions to postfix? A. To simplify calculations B. To eliminate parentheses C. To make it easier for computers to evaluate D. All of the above Show Answer 2. Which data structure is primarily used in converting infix expressions ...
The idea is to use thestack data structureto convert an infix expression to a postfix expression. The stack is used to reverse the order of operators in postfix expression. The stack is also used to hold operators since an operator can’t be added to a postfix expression until both of its...
广义上infix是给user看的,prefix和postfix很大程度上是给编译器看的。具体地,对于单操作符运算,其实用的是prefix(比如取非),当然常见的prefix/postfix就是++、--,但是python中没有这个操作符。 有用 回复 查看全部 1 个回答 推荐问题 字节的 trae AI IDE 不支持类似 vscode 的 ssh remote 远程开发怎么办? 尝...
After 13 years of doing Lisp and 3 or 4 years of Python, I agree: I prefer writing Lisp, but Python is easier to read.-John Wiseman LISP: ... mythically from ‘Lots of Irritating Superfluous Parentheses’Jargon File [If only] we could find characters or signs suited for expressing all...
#print("Postfix:", postfix) while len(stack) > 0: top = stack.pop() if top in OPERATORS.keys(): postfix.append(top) return postfix Please, don't tell me anything about the docstrings, because I actually removed them from my code to make it clearer. ...
Se o token atual for um operando, anexe-o no final da expressão postfix. Se o token atual for um operador, coloque-o no topo da Stack. Antes de fazer isso, primeiro pule da Stack até que tenhamos um operador de menor precedência no topo, ou a Stack fique vazia. Acrescente ca...