* @param root: A Tree * @return: Inorder in ArrayList which contains node values. */vector<int>inorderTraversal(TreeNode * root){// write your code herevector<int> result; traverse(root, result);returnresult; }/
2.2 last.right 不为 null,说明之前已经访问过,第二次来到这里,表明当前子树遍历完成,保存 cur 的值,更新 cur = cur.right public List<Integer> inorderTraversal3(TreeNode root) { List<Integer> ans = new ArrayList<>(); TreeNode cur = root; while (cur != null) { //情况 1 if (cur.left ...
binary-tree-inorder-traversal /** * * @author gentleKay * Given a binary tree, return the inorder traversal of its nodes' values. * For example: * Given binary tree{1,#,2,3}, 1 \ 2 / 3 * return[1,3,2]. * Note: Recursive solution is trivial, could you do it iteratively?
vector<int> inorderTraversal(TreeNode* root) { vector<int> res; inorder(res,root); return res; } private: void inorder(vector<int>& res,TreeNode* root){ if(root==NULL) return; inorder(res,root->left); res.push_back(root->val); inorder(res,root->right); } }; 1. 2. 3. ...
Given a binary tree, return the inorder traversal of its nodes' values. For example: Given binary tree [1,null,2,3], return [1,3,2]. Note: Recursive solution is trivial, could you do it iteratively? 解析 嘻嘻,最近因为马上要面试,就回忆一下树的遍历,快排,最长公共子序列,八皇后之类的基...
二叉树中序遍历的非递归算法和前序遍历思想差不多都是使用栈结构进行求解,参考Leetcode: Binary Tree Preorder Traversal(二叉树前序遍历)。 非递归解法(C++): class Solution { public: vector<int> inorderTraversal(TreeNode *root) { vector<int> result; ...
* Definition for a binary tree node. * public class TreeNode { * int val; * TreeNode left; * TreeNode right; * TreeNode(int x) { val = x; } * } */classSolution{public List<Integer>postorderTraversal(TreeNode root){Deque<Integer>result=newLinkedList<>();if(root==null){returnnewA...
Same Tree -https://leetcode.com/problems/same-tree/ Invert/Flip Binary Tree -https://leetcode.com/problems/invert-binary-tree/ Binary Tree Maximum Path Sum -https://leetcode.com/problems/binary-tree-maximum-path-sum/ Binary Tree Level Order Traversal -https://leetcode.com/problems/binary-...
名字叫做, morrois traversal, 自己写了下: My code: /** * Definition for a binary tree node. * public class TreeNode { * int val; * TreeNode left; * TreeNode right; * TreeNode(int x) { val = x; } * } */publicclassSolution{publicList<Integer>inorderTraversal(TreeNoderoot){List...
you'll often need some way to get access to each object in the collection. In fact, depending on the collection, you may want several ways to access each object such as front to back, back to front, preorder or postorder. To keep the collection simple, the traversal code itself is oft...