1.Write a C# program to implement a stack with push and pop operations. Find the top element of the stack and check if the stack is empty or not. Click me to see the sample solution 2.Write a C# program to sort the elements of a given stack in descending order. ...
inStack.push(x); } 复杂度分析如下: 时间复杂度:O(1)O(1) 空间复杂度:O(n)O(n),需要额外的空间用于存储队列元素 出队(pop) 在入队时,由于先入的元素处于输入栈inStack的栈底,因此,为了能够弹出栈底的元素实现出队操作,需要将输入栈inStack中的元素弹出并压入到输出栈outStack中。此时,输出栈outStack...
将元素依次进入队1,进入时用top元素保存当前进入的元素; 如下图: push操作的演示 然后演示pop()操作; 先将除队1中的最后一个元素出队并进入队2,入队2时用top存储入队元素; 再将队列1和队列2进行互换即可。 如下图: pop操作的演示 代码 importjava.util.LinkedList;importjava.util.Queue;classMyStack{private...
stk.push(6);stk.push(5);stk.push(3);stk.push(1);stk.display();// Display the elements in the stackcout<<"\nRemove 2 elements from the stack:\n";stk.pop();stk.pop();stk.display();// Display the updated stackcout<<"\nInput 2 more elements:\n";stk.push(8);stk.push(9);...
push操作的演示 然后演示pop()操作; 先将除队1中的最后一个元素出队并进入队2,入队2时用top存储入队元素; 再将队列1和队列2进行互换即可。 如下图: pop操作的演示 代码 代码语言:javascript 复制 importjava.util.LinkedList;importjava.util.Queue;classMyStack{privateQueue<Integer>queue_1=newLinkedList<>()...
push(x) -- Push element x to the back of queue. pop() -- Removes the element from in front of queue. peek() -- Get the front element. empty() -- Return whether the queue is empty. Notes: You must use only standard operations of a stack -- which means only push to top, peek...
(sb.length()-2); return sb.toString(); } public static void main(String[] args) { Stack<String> stack = new Stack<String>(11); stack.push("hello"); stack.push("world"); System.out.println(stack); stack.pop(); System.out.println(stack); stack.pop(); System.out.println(stack)...
pop(st) Dequeue an element from the queue. C++ Java Python #include<bits/stdc++.h> using namespace std; class Stack { queue<int>q; public: void push(int val); void pop(); int top(); bool empty(); }; void Stack::push(int val) { int s = q.size(); q.push(val); for ...
push 2. pop 3. peek 4. check empty 5. size 1 Enter integer element to push 5 Stack = 5 Do you want to continue (Type y or n) y Linked Stack Operations 1. push 2. pop 3. peek 4. check empty 5. size 1 Enter integer element to push 33 Stack = 33 5 Do you want to ...
push(x); } public int pop() { if (outStack.isEmpty()) { in2out(); } return outStack.pop(); } public int peek() { if (outStack.isEmpty()) { in2out(); } return outStack.peek(); } public boolean empty() { return inStack.isEmpty() && outStack.isEmpty(); } private ...