问如何在android.bp中编写条件ifeq ($(filter-out tt_%，$(TARGET_PRODUCT))，)EN在编程时，实际上...
ifeq ($(strip $(foreach v, 3.81% 3.82% 4.%, $(filter $v, $(MAKE_VERSION))), )
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也是我第一次管理GNU Make，所以我想解释一下我的problem.perhaps，你可以帮我在这条隧道的尽头找到一丝...
ifeq ($(filter $(cond1) $(cond2),yes),) x := 2 else x := 1 endif Share Improve this answer Follow edited Oct 29, 2014 at 20:26 answered Oct 29, 2014 at 20:16 Mark Galeck 6,33733 gold badges3232 silver badges5959 bronze badges Add a comment 1 Alternate answer is:...
44 $(CC) -E -MM $(filter %.c,$^) > $@.tmp;\ 45 sed's,\(.*\)\.o[ :]*, objs/\1.o: ,g'< $@.tmp > $@ ;\ 46 $(RM) $(RMFLAGS) $@.tmp 47 clean: 48 $(RM) $(RMFLAGS) $(DIRS) 1. 2. 3. 4. 5.
Makefile中的ifeq 多条件使用 网上关于makefile中ifeq的介绍已经很多了,为什么我还要在写这篇文章,因为他们只说了if else两种条件的情况,并没有讲多于两种条件情况的使用。 多于两种情况的使用很简单,害我尝试很多种方法,如ifeq elifeq等等这些。其实就如同c中的if
filter $(filter <pattern...>,<text>) 这是一个过滤函数,这个函数执行时,首先会根据空格或者tab键或者回车换行符进行分割,然后一一的进行filter函数的操作。然后遍历每一个被分割出来的字符,如果不满足pattern的规则的话对应的字符就会被过滤掉。 s = a.c abo.c s.o s.y x.o x.y ...
I'm trying to use find_j=$(findstring j,$(filter-out --%,$(MAKEFLAGS))) to find if there is -j option, so when I echo $(find_j) the value is j but when I compare it ifeq (j, $(find_j)) this returnes false I cant understand where is the problem my version of make is...
version of the Make manual as an example use of the filter function. Also, one of the situation I'm trying to test for is the empty string (in my previous example, say Y=`'), which I believe I can't test in this manner: