If f(x)=cosxcos2xcos4xcos8xcos16x, then f'(π4) is A √2 B 1√2 C 1 D none of these Video Solution Struggling with Differentiation ? Get free crash course Text SolutionGenerated By DoubtnutGPT The correct Answer is:A To find f′(π4) for the function f(x)=cosxcos2xcos4xco...
译文:若函数 f(x)=x-asinx 在全体实数范围内是增函数,则参数a的 取值范围是 解: f'(x)=1-acosx . 当 |a|1 时,导函数 f'(x) 恒为正值,所以f(x)是增函数; 当a=1时,导函数 f'(x) 仅在x=2kn时为零,其余点上取值为正,所以f(x) 是增函数; 当a=-1时,导函数 f'(x) 仅在x=(2k+...
If f(x)=xcosx, find f''(x). 03:21 The displacement of a particle is given by y=(6t^2+3t+4)m, where t is ... 01:15 The velocity of a particle is given by v=12+3(t+7t^2). What is the acc... 01:44 A particle starts from origin with uniform acceleration. Its displ...
( x )= cosx+2sin x+. 3 = 1-sina+2sin x+.3 [-π/(3),θ] ∵1=sin111 , ∈[-π/(3),0] ,则原函数可转化为y=-r+ 2+.3+1.结合函数 =sin和 =-1^2+21+⋯3+1 的图 象(图略) 知 t∈[-1/2,-1,1,1] " i_1=-π/(3) 时, t=sin1=-3/2 ,此时 =1/4 ;...
Solution for Find f if f"(x) =2 + cos(x), f(0) = 10, f(t/2) = -5. f(x) = |
Transcribed Image Text:Find f if f"(x) = 2+ cos(x), f(0) = 2, ƒ(x/2) = -2. f(x) = Expert Solution Knowledge Booster Learn more about Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, calculus and...
解:中 f(x)=2sin2x-2V3sin xsin(x-)-|||-2=2sin2x+2 3sin xcosx=1-cos2x+5sin2x-=1+2sin(2x-)所以f(x)=1+2sin(2x-)中0x-|||-2元-|||--|||-3元ssin(2x-6)1-|||-2 即0f(x)≤3f(x)-m2即m-2f(x)2+m在区间2π-|||-3上恒成立2+m3-|||-m-2≤0解得1m≤2故...
If f(x)=∣cosx∣, expand f(x) as a Fourier series in the interval (−π,π). solve question no 1 Show transcribed image text There are 2 steps to solve this one. Solution Share Step 1 Question is f(x)=∣cosx∣, expand f(x) as a Fourier series...
Answer to: If f(x) = tan(x) + sec(x), find f'((3pi)/4). A. 2 - 2sqrt 2 B. -2 - sqrt 2 C. 2 - sqrt 2 D. 2 + sqrt 2 E. 2 sqrt 2 - 2 By signing up,...
Determine iff(x)=cosxis the sum of its taylor series ata=π2. Taylor Series: The Taylor series is a series expansion of a function at a point. If we consider a functionf(x)about a pointx=a, then its Taylor series expansion is given by ...