Identify three valid host addresses in the 192.168.27.0 network with a subnet mask of 255.255.255.240. () A. 192.168.27.33 B. 192.168.27.112 C. 192.168.27.119 D. 192.168.27.126 E. 192.168.27.175 F. 192.168.27.208 相关知识点: 试题来源: ...
Identify three valid host addresses in the 192.168.27.0 network with a subnet mask of 255.255.255.240. () A.192.168.27.33 B.192.168.27.112 C.192.168.27.119 D.192.168.27.126 E.192.168.27.175 F.192.168.27.208 查看答案 更多“Identify three valid host addresses in the 192.168.27.0 network with a ...
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$n =2;# step$m =0;# array idfor($mask = $subnet['mask'] +1; $mask <= $maxMask; $mask++) {# set vars$opts[$m]['mask'] = $mask; 开发者ID:btorresgil,项目名称:phpipam,代码行数:31,代码来源:manageSubnetsplit.php 示例2: searchSubnets ▲点赞 5▼ /** * Search subnets */f...