I am given the following second-order ODE and I want to use ode45 and by not creating a function file. I am given the equation above, a timespan t, and initial y and dy values. I first set up my dydt into a matrix [y1' y2']" dydt = [y(2); eps...
I currently have this code although I'm not sure if it's correct and when I ran it, MATLAB returned "Undefined function or variable 'xin'." function Yd= tennispin(t,Y) %constants alpha = 80*pi/180; r = 3.35; w = 193; A = 3.35^2*pi; Cd = 0.55; rho = 1.21; m = 0.0...
how to use derivative of function using gradient?. Learn more about derivative, matlab, gradient, ode
MATLAB Online에서 열기 I tried to solve these ODE equations but there is an error! This is my code: 테마복사 syms x1(w) x2(w) x3(w) T=773.15; R=1.314; K=(3.35e+24)*exp(-(70e+3)/(1.987*T)); Keq=exp(53.47-(27330/T)); ode1=diff(x1,w)==((-K*...
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Open in MATLAB Online I am trying to execute the code below, a finite time lyapunov exponent code with plot generations. However, at this point: ThemeCopy % Use the indices to get the states at these map returns. state_lowFTLE = xReturns_running...
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Open in MATLAB Online If you insert the line ThemeCopy size(dYdt(tspans(1),initial_conditions)) before the call to ode45, you will see that your function dYdt still returns a matrix of size 2x365 instead of a vector of size 2x1. So here see...
Yes, there are several ways to automatically adjust the time step size in Matlab. One way is to use the ode23, ode45, or ode113 functions to solve differential equations with variable time steps. Another way is to use the solve function with the MaxStep option to specify...
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