마감:MATLAB Answer Bot2021년 8월 20일 Hello, I am currently trying to solve an ODE for two differential equations. These equations represent body mass and body energy in an animal. I have quite a few parameters necessary to solve these, one being feeding ...
MATLAB Online에서 열기 I am simulation a system of ODEs in which one parameter is a function of time (similar to a switch function) and others are constants. Below is the MWE and it gives me various errors. 테마복사 function dxdt = Eq(~,x,par,h...
it doesn't change anything to my plot! => which made me think that matlab probably doesn't use the solution of myODE2 for solving myODE1. Any idea about what I am missing out? Furthermore, I would like the solutions u to be in the interval [0,1] but I couldn't figure ...
You have to specify your problem well enough to be solvable. As of now you have told us that...
now I got the error: odearguments at 115 @(T,H)(((G0*L-H)/TAU)-((PIN/ESAT)*(EXP(H)-1))) returns a vector of length 30, but the length of initial conditions vector is 1. The vector returned by @(T,H)(((G0*L-H)/TAU)-((PIN/ESAT)*(EXP(H)-1))) and the initial ...
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Ah, that actually wasn't what I was thinking (I don't know why, b/c in retrospect your question makes perfect sense). Anyway, that actually makes the answer fairly easy: yes. See Thanks
Open in MATLAB Online Since this was inspired by the valuable comment of Walter Roberson to my original answer, I am posting this solution as a separate answer. So it turns out the for-loop solution actually performs 6-8x faster than interp1 inside the ODE RHS function! ...
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