Implicit functions are those where both variables are expressed on either side of the equation, and can be simplified through a process known as implicit differentiation. See how this process can find derivatives of implicit functions and explore the steps involved. ...
How does the method of implicit differentiation use? 中学英语课外阅读阅读材料摘要:doi:10.1016/0040-6031(74)80046-8YuxueLiang中学生数学:高中版
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Find the derivative of the above equation using implicit differentiation with respect to x. The derivative of (x-h)^2 + (y-k)^2 = r^2 is 2(x-h) + 2(y-k)dy/dx = 0. The derivative of the circle from step one would be 2x+ 2(y-1)*dy/dx = 0. Step 3 Isolate the dy/dx...
Find the equation for dydx. Since the equation is implicitly defined, we use implicit differentiation. 2x+2ydydx=02ydydx=−2xdydx=−2x2ydydx=−xy Step 3 Find the slope of the tangent line at the point of tangency. At the point (2,2√3), the slope of the tangent line is...
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