n= sum([int(i)**2foriinstr(n)])returnn==1 Runtime:60 ms, faster than8.31% of Python3 online submissions for Happy Number. Memory Usage:14 MB, less than20.99% of Python3 online submissions for Happy Number. classSolution:defisHappy(self, n: int) ->bool:whilen> 6: next=0whilen...
代码 1classSolution {2public:3boolisHappy(intn) {4set<int>dict;5while(!dict.count(n)){6dict.insert(n);7intsum =0;8while(n >=1){9sum += (n %10) * (n %10);10n /=10;11}12n =sum;13if(sum ==1)14returntrue;15}16returnfalse;17}18};...
class Solution: def isHappy(self, n: int) -> bool: # used 维护已出现的数字集合 used: Set[int] = set() #当 n 未出现过时,继续计算下一个数 while n not in used: # 标记 n 已出现过 used.add(n) # 计算下一个数,即求 n 的每一位的平方和 nxt: int = 0 #当 n 不为 0 时,则...
[LeetCode]Happy Number Question Write an algorithm to determine if a number is “happy”. A happy number is a number defined by the following process: Starting with any positive integer, replace the number by the sum of the squares of its digits, and repeat the process until the number eq...
19 is a happy number 1^2 + 9^2 = 82 8^2 + 2^2 = 68 6^2 + 8^2 = 100 1^2 + 0^2 + 0^2 = 1 LeetCode上的原题,请参见我之前的博客Happy Number。 解法一: classSolution {public:/** * @param n an integer * @return true if this is a happy number or false*/boolisHap...
本题可在LeetCode上OJ,链接 Happy Number, 感谢 @牧码人小鹏 题目描述: Write an algorithm to determine if a number is "happy". A happy number is a number defined by the following process: Starting with any positive integer, replace the number by the sum of the squares of its digits, and...
leetcode 202. Happy Number class Solution { public: bool isHappy(int n) { if(n <= 0) return false; set<int> res; while(res.count(n) == 0){ res.insert(n); int num = 0; while(n != 0){ num += (n%10)*(n%10);
Solution s; int result; if (s.isHappy(m)) { cout << m << " " << "is a happy number" << endl; } else { cout << m << " " << "is not a happy number" << endl; } //strRes = s.findRepeatedDnaSequences(s1); //cout << "The result is : " << ...
Leetcode - Happy Number 最近已经开始紧张的期末复习了,但是看到大家都在进行编程训练,为今年九月找工作做准备,我的心不能定。因为我知道,英国的成绩对我无意义,但是编程能力是我以后吃饭的家伙,我绝对不能落下。 之前一直在上普林斯顿的算法课。最后三周的课,每次上耗时太长,实在抽不出时间,而且自己已经明显过...
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