https://leetcode.com/problems/happy-number/ https://leetcode.com/problems/happy-number/discuss/56913/Beat-90-Fast-Easy-Understand-Java-Solution-with-Brief-Explanation https://leetcode.com/problems/happy-number/discuss/56917/My-solution-in-C(-O(1)-space-and-no-magic-math-property-involved-) ...
leetcode 202 Happy Number Write an algorithm to determine if a number is "happy". A happy number is a number defined by the following process: Starting with any positive integer, replace the number by the sum of the squares of its digits, and repeat the process until the number equals 1...
bool isHappy(int n) { if(n <= 0) return false; set<int> res; while(res.count(n) == 0){ res.insert(n); int num = 0; while(n != 0){ num += (n%10)*(n%10); n = n/10; } if(num == 1) return true; n = num; } return false; } }; 1. 2. 3. 4. 5. 6....
链接:http://leetcode.com/problemset/algorithms/ 题解: 判断一个数字是否为Happy Number。这道题跟求无限循环小数很像,最好维护一个HashSet,假如遇见重复,则返回false。否则替换n为digits square root sum,当n == 1时循环结束返回true。 Time Complexity - O(n), Space Complexity - O(n)。
leetcode:HappyNumber,House Robber 1.Happy Number 这个题中收获2点: 1.拿到题以后考虑特殊情况,代码中考虑1和4,或者说<6的情况,动手算下。(可能要在代码一步步测试中发现,目前还不知道怎么知道这些特殊情况) 2.数字的每一位时,n%10,n/10。(3/7的余数为3,7/3的余数为4) ...
详见:https://leetcode.com/problems/happy-number/description/ Java实现: 1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 classSolution { publicbooleanisHappy(intn) { Set<Integer> s=newHashSet<Integer>(); while(n!=1){
题目地址:https://leetcode-cn.com/problems/longest-happy-string/题目描述如果字符串中不含有任何 'aaa','bbb' 或'ccc' 这样的字符串作为子串,那么该字符串就是一个「快乐字符串」。给你三个整数 a,b,c,请你返回 任意一个 满足下列全部条件的字符串 s:...
C -> 3 ... Z -> 26 AA -> 27 AB –> 28 这道题非常之简单,比起原题来简单不少,非常直接,就是一个进制的问题。代码奉上 classSolution {public:inttitleToNumber(strings) {if(s =="")return0;intresult =0;inti =0;while(s[i] !='\0') ...
"https://leetcode.com/problems/happy number/" 给定一个数字,每一次拿出这个数字 abc 的每一位执行 $a^2 + b^2 + c^2$ ,得到一个新的数,然后再把新的数进行逐位平方取和,如果最后面得到的值为1,那么这个数就是 hap
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