1a =raw_input().strip()2b =raw_input().strip()3cnt =0;4foriinxrange(len(a)):5cnt += 1ifa.find(b, i, i+len(b))!= -1else06printcnt
Find a string defcount_substring(string,sub_string):counter,sum=0,0for_inrange(0,len(string)):ifmatcher(string[counter:(len(sub_string)+counter)],sub_string):sum=sum+1counter=counter+1returnsumdefmatcher(sliced_str,sub_string):returnsliced_str==sub_string Let's consider this is our targ...
在Hackerrank中使用Python解决重复字符串问题,可以使用字符串的切片和乘法操作来实现。以下是一个示例代码: ```python def repeat_string(s, n): ...
Python Functionals Reduce Function 30 Medium Solution.py Regex and Parsing Detect Floating Point Number 20 Easy Solution.py Regex and Parsing Re.split() 20 Easy Solution.py Regex and Parsing Group(), Groups() & Groupdict() 20 Easy Solution.py Regex and Parsing Re.findall() & Re.finditer(...
#计算字符串中有效的表达式 print(eval('pow(2,2)')) print(eval('2+2')) #将字符串转成相应的对象(如list、tuple、dict和string之间的转换) a="[[1,2], [3,4], [5,6], [7,8], [9,0]]" b="(1,2,3,4)" c="{1:'xx',2:'yy'}" print(eval(a)) print(eval(b)) print(eval...
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代码语言:python 代码运行次数:0 复制Cloud Studio 代码运行 import re pattern = r'\.' # 正则表达式模式,匹配句点字符 text = 'This is a sentence. This is another sentence.' matches = re.findall(pattern, text) # 使用re.findall()函数查找所有匹配项 print(matches) # 输出匹配结果 运行上述代码...
Hackerrank Python Tutorial Solutions. Contribute to sonmez-hakan/hackerrank-python development by creating an account on GitHub.
题目链接刷刷Python基本功...列表解析附上代码:1 x = int(input())2 y = int(input())3 z = int(input())4 n = int(input())5 print [[i, j, k] for i in xrange(x+1) for j in xr
I think when the given number is given as binary string like "1110" instead of 14. The following solutions have critical problems to manipulate bit operations. Also when the length of binary string is like 100000, I think those can be TLE. I suggest a iterative linear ti...