1a =raw_input().strip()2b =raw_input().strip()3cnt =0;4foriinxrange(len(a)):5cnt += 1ifa.find(b, i, i+len(b))!= -1else06printcnt
Find a string check this def count_substring(string, sub_string): count =0 for i in range(0,len(string)-len(sub_string)+1): try: if string[i:i+len(sub_string)]==sub_string: count+=1 except IndexError: break return count
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function main(input) { //Enter your code here var num = parseInt(input, 10);//This line expects input to be a string so convert to an int as per problem var res=1; for(var i=num;i>1;i--) { res *= i; } process.stdout.write(res);//This is how you write output. } 编...
其实iostream> #include <string> using namespace std; inline string dbtest(int a)...
问HackerRank -拾取数EN我对编程很陌生，这是我在这里的第一个问题。您的问题是，当您构建您的子数组...
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#计算字符串中有效的表达式 print(eval('pow(2,2)')) print(eval('2+2')) #将字符串转成相应的对象(如list、tuple、dict和string之间的转换) a="[[1,2], [3,4], [5,6], [7,8], [9,0]]" b="(1,2,3,4)" c="{1:'xx',2:'yy'}" print(eval(a)) print(eval(b)) print(eval...
One string must be “mn" and other be “op”. The length are a=2 and b=2, so the difference is less than 1. Nocharacters are common between the strings, so both must be changed. One string must be “xy” and the other be “yx”. The length are a=2 and b=2, so the diffe...