long arrayManipulation(int n, vector<vector<int>> queries) { vector<long> arr(n, 0); long max_val = 0; for(auto q : queries) { int l = q[0]-1, r = q[1]-1; for(int i = l; i <= r; ++i) { arr[i] += q[2]; if(max_val < arr[i]) { max_val = arr[i]; ...
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C++足够快，你可以摆脱低效。Python更慢，这个算法不再足够好。不是将数据存储在值数组中，而是存储在增...
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Tony's Log HackerRank - "Sam and sub" Brutal-force solution is not hard to think about. But linear space input usually indicates O(n) DP solution. State design: dp[i]: total sum until index i; and then you need some number manipulation to figure out the equation....
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