arrayManipulation has the following parameters: int n- the number of elements in the array int queries[q][3]- a two dimensional array of queries where eachqueries[i]contains three integers,a,b, andk. Returns int- the maximum value in the resultant array ...
long arrayManipulation(int n, vector<vector<int>> queries) { vector<long> arr(n, 0); long max_val = 0; for(auto q : queries) { int l = q[0]-1, r = q[1]-1; for(int i = l; i <= r; ++i) { arr[i] += q[2]; if(max_val < arr[i]) { max_val = arr[i]; ...
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相反，您可以将查询拆分为启动和停止事件，然后对这些事件进行排序。最后迭代这些事件以获得最大累积值。
Tony's Log HackerRank - "Sam and sub" Brutal-force solution is not hard to think about. But linear space input usually indicates O(n) DP solution. State design: dp[i]: total sum until index i; and then you need some number manipulation to figure out the equation....
[i + 2][j + 1] + arr[i + 2][j + 2]; res = max(sum, res); } } return res; } int main() { vector<vector<int>> arr(6, vector<int>(6)); for (auto& r : arr) { for (auto& c : r) { cin >> c; } } auto res = solution(arr); cout << res << endl; ...
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danhenriquesc Update README to add Minimum Swaps 2 Python Solution (danhenriquesc#136) 723581c· Oct 19, 2021 History49 Commits algorithms cracking_the_coding_interview data_structures functional_programming/introduction olx_code_and_the_curious sql/basic_select week_of_code_37 CONTRIBUTI...