在Go语言中,将map转换为JSON字符串是一个常见的操作,通常用于网络传输或数据存储等场景。以下是详细的步骤,并包含相应的代码片段: 创建一个Go语言的map: 首先,定义一个map并初始化一些键值对。这里以string为键(key),以任意类型(例如int、string等)为值(value)的map为例: go m := map[string]interface{}{ ...
// map to json package main import ( "encoding/json" "fmt" ) func main() { s := []map[string]interface{}{} m1 := map[string]interface{}{"name": "John", "age": 10} m2 := map[string]interface{}{"name": "Alex", "age": 12} s = append(s, m1, m2) s = append(s, ...
beforeMap := map[string]interface {}{ "id":"123", "user_name":"酒窝猪", "address":[]map[string]interface{}{{"address": "address01"}, {"address": "address02"}}, } var afterStruct =UserInfoVo{} before := time.Now() marshal, err := json.Marshal(beforeMap) if err!=nil{ fmt...
main.Person{Name:"Foo", Age:21, Emails:[]string{"one@gmail.com", "two@gmail.com", "three@gmail.com"}, Extra:map[string]string{"twitter":"Foo"}} 这种方法可能是最常用的,可以毫不费力地将map[string]interface{}映射到我们定义的结构。 在这里,我们并没有为每个字段指定标签,而是让mapstructure...
如果输入是 JSON 字符串,我们首先将其解析为map[string]interface{}格式,然后将其映射到结构中。 func jsonDecode() { var jsonStr = `{ "name": "Foo", "age": 21, "gender": "male" }` type Person struct { Name string Age int Gender string ...
先将map转换成JSON,再通过 JSON 转换成struct 操作有点繁琐 func TestMapToStructByJson(t *testing.T) { beforeMap := map[string]interface {}{ "id":"123", "user_name":"酒窝猪", "address":[]map[string]interface{}{{"address": "address01"}, {"address": "address02"}}, ...
可以使用标准库中的json包将字符串转换为JSON。具体代码如下: package main import ( "encoding/json" "fmt" ) func main() { str := `{"name": "Alice", "age": 30}` data := make(map[string]interface{}) json.Unmarshal([]byte(str), &data) ...
将map 转换为 json 字符串的实现为: func Marshal(m map[string]interface{}) string { if byt, err := json.Marshal(m); err != nil { return "" } else { return string(byt) } } 将json 字符串转换为 map 的实现为: func Unmarshal(str string) (map[string]interface{}, error) { ...
golang json 为map[string] interface{} json字符串: {"sn":1,"ls":false,"bg":0,"ed":0,"ws":[{"bg":0,"cw":[{"sc":0,"w":"还"}]},{"bg":0,"cw":[{"sc":0,"w":"有点"}]},{"bg":0,"cw":[{"sc":0,"w":"眼熟"}]}]}...
2:go解析处理json转map(多层嵌套) AI检测代码解析 //jsonStr为上面的json字符 printInfo := make(map[string]interface{}) jsonErr = json.Unmarshal([]byte(addressInfo.PrintInfo), &jsonStr) if jsonErr != nil { fmt.Println("json解析错误") ...