// To unmarshal JSON into an interface value, // Unmarshal stores one of these in the interface value: // // bool, for JSON booleans // float64, for JSON numbers // string, for JSON strings // []interface{}, for JSON arrays // map[string]interface{}, for JSON objects // nil ...
wordCloudJson := convert.ToString(data[0]["word_cloud_json"]) words := make(map[string]interface{}) err = json.Unmarshal([]byte(wordCloudJson), &words) if err != nil { logu.CtxError(ctx, error_code.ProcessError, "GetBrandWordCloud Unmarshal", "wordCloudJson:%v,error: %v", wordClou...
m := make(map[string]interface{}) err := json.Unmarshal([]byte(jsonStr), &m) if err != nil { panic(err) } var result Person err = mapstructure.Decode(m, &result) if err != nil { panic(err.Error()) } fmt.Printf("%#v\n", result) } 结果: main.Person{Name:"Foo", Age:...
funcgetObjFuncParam(rw http.ResponseWriter,br[]byte)(string,string,map[string]interface{},error){input:=new(QueryModel)err:=json.Unmarshal(br,&input)iferr!=nil{fmt.Errorf("获取参数错误")}returninput.Obj,input.Func,input.Param,nil} 看起来没问题,然后看下getFuncResult方法,整个方法是做整体后台...
Name string Age int Gender string } m := make(map[string]interface{}) err := json.Unmarshal([]byte(jsonStr), &m) if err != nil { panic(err) } var result Person err = mapstructure.Decode(m, &result) if err != nil {
可以使用标准库中的json包将字符串转换为JSON。具体代码如下: package main import ( "encoding/json" "fmt" ) func main() { str := `{"name": "Alice", "age": 30}` data := make(map[string]interface{}) json.Unmarshal([]byte(str), &data) ...
通过JSON 进行转换 先将 转换成,再通过 JSON 转换成 操作有点繁琐 func TestMapToStructByJson(t *testing.T) { beforeMap := map[string]interface {}{ "id":"123", "user_name":"酒窝猪", "address":[]map[string]interface{}{{"address...
json解析 json转换为map 编码工具json-to-go:json转换成go struct工具 Go的json解析:Marshal与Unmarshal Go的json解析:Marshal与Unmarshal 原文链接: Json(Javascript Object Nanotation)是一种数据交换格式,常用于前后端数据传输。任意一端将数据转换成json 字符串,另一端再将该字符串解析成相应的数据结构,如string类...
将map 转换为 json 字符串的实现为: func Marshal(m map[string]interface{}) string { if byt, err := json.Marshal(m); err != nil { return "" } else { return string(byt) } } 将json 字符串转换为 map 的实现为: func Unmarshal(str string) (map[string]interface{}, error) { ...
通过JSON 进行转换 先将map转换成JSON,再通过 JSON 转换成struct 操作有点繁琐 func TestMapToStructByJson(t *testing.T) { beforeMap := map[string]interface {}{ "id":"123", "user_name":"酒窝猪", "address":[]map[string]interface{}{{"address": "address01"}, {"address": "address02"}...