百度试题 结果1 题目friend istream &operator>> 相关知识点: 试题来源: 解析 这个是C++的语法:定义了一个友元函数,operator >>,这个函数本身又是对操作符>>的重载,其返回的类型是istream的一个引用.涉及的概念:类、友元,操作符重载,流以及引用.反馈 收藏 ...
【答案】：&是引用的符号。相当于别名的意思。返回引用是为了能让操作符连用，运行会快一些。<p 如定义Screen s1,s2；<p cin>>s1>>s2;
试题源程序文件清单如下: #include #include using namespace std; class MiniString public: friend ostream &operator output friend istream &operator char temp[ 100]; //用于输入的临时数组 temp[0]='/0'; //初始为空字符串 input>>setw(100)>>temp;...
friend ostream&operator<<(ostream&out,constposition&s); friend istream&operator>>(istream&in,position&s); intx; inty; }; voidmain() { position m(3,4); cout<<m<<endl; cout<<"输入x,y\n"; cin>>m; cout<<m<<endl; } position ::position(intm,intn) :x(m),y(n) {} ostream...
顺序表结点结构类templateclassstructVertex顶点的定义Tdata顶点的名字Edgeadj边链表的头指针邻接表类templateclassclassGraphlnkpublicGraph图的类定义friendistreamoperatoristream输入friendostrea
friend ostream& operator <<(ostream &os,const Base &obj); }; istream& operator >>(istream &is,Base &obj) { is>>strVal; return is; } ostream& operator <<(ostream &os,const Base &obj) { os<<obj.strVal; return os; } void main() ...
istream& operator >>(istream &is,Base &obj) { is>>strVal; return is; } ostream& operator <<(ostream &os,const Base &obj) { os<<obj.strVal; return os; } void main() { Base b; cin>>b; cout<<"Printing the value\n";
friend ostream& operator <<(ostream& os, Matrix const& rhs);friend istream& operator >>(istream& is, Matrix & rhs);};Matrix::Matrix(int a1, int b1, int c1, int d1){ a = a1;b = b1;c = c1;d = d1;} Matrix& Matrix::operator +=(Matrix const& rhs){ this->a+...
std::ostream&,constSet<T>&);template<classT>classSet{public:Set(){size=0;data=newT[M_size=Capacity];}Set(intc){size=0;data=newT[M_size=c];}friendstd::istream&operator>>(std::istream&,Set<T>&);friendstd::ostream&operator<<(std::ostream&,constSet<T>&);T&operator[](int);int...
void display(){cout<<real<<"+"<<imag<<"i"<<endl;} friend ostream& operator<<( ostream& os,Complex& c){ os<<c.real<<"+"<<c.imag<<"i"; return os; } friend istream& operator>>(istream& is,Complex& c){ is>>c.real>>c.imag; ...