The frequency of an element is the number of times it occurs in an array. You are given an integer arraynumsand an integerk. In one operation, you can choose an index ofnumsand increment the element at that index by1. Returnthe maximum possible frequency of an element after performing at...
Two Sum II - Input array is sorted 0.531 简单 24 #128 Longest Consecutive Sequence 0.483 困难 25 #120 Triangle 0.641 中等 26 #169 Majority Element 0.628 简单 27 #48 Rotate Image 0.674 中等 28 #442 Find All Duplicates in an Array 0.644 中等 29 #289 Game of Life 0.696 中等 30 #105 Co...
[LeetCode 1224] Maximum Equal Frequency Given an arraynumsof positive integers, return the longest possible length of an array prefix ofnums, such that it is possible to remove exactly one element from this prefix so that every number that has appeared in it will have the same number of occ...
操作后的最高频元素必定可以是数组中已有的某一个元素。 提示1 解释 我们用 xi 来表示 nums 数组中下标为 i 的元素。 如果可以将数组内的一系列元素 xi1,…,xik 全部变为 y,假设这些元素中的最大值为 x,那么我们一定可以将这些数全部变成 x,此时频数不变且操作次数更少。 提示2 优先操作距离目标值最近...
void push(int val)pushes an integervalonto the top of the stack. int pop()removes and returns the most frequent element in the stack. If there is a tie for the most frequent element, the element closest to the stack's top is removed and returned. ...
【leetcode】1224. Maximum Equal Frequency 题目如下: Given an arraynumsof positive integers, return the longest possible length of an array prefix ofnums, such that it is possible to remove exactly one element from this prefix so that every number that has appeared in it will have the same ...
ImplementFreqStack, a class which simulates the operation of a stack-like data structure. FreqStackhas two functions: push(int x), which pushes an integerxonto the stack. pop(), which removes and returns the most frequent element in the stack. ...
Given an array nums of positive integers, return the longest possible length of an array prefix of nums, such that it is possible to remove exactly one element from this prefix so that every number that has appeared in it will have the same number of occurrences. ...