yfrac(sin 16x)(16sin x),(y^(prime))=frac(16cos 16xsin x - cos xsin 16x)(16((sin )^2)x); (4) y=frac(ln sin x)(ln x),(y^(prime))=frac(xcos xln x- sin xln sin x)(xsin x((left( ln x right))^2)). (1) y=3x+1-frac1((x^3)),(y^(prime))=3+frac...
https://socratic.org/questions/how-do-you-solve-x-3-5-1 x=1 Explanation: We can use some rules to find out. First rule we'll use is x−1=x1 : x−53=1 x531=11 ... What is (x−21)−4 ? https://socratic.org/questions/...
Verify the identity: 11−sin2x=1+tan2x Question: Verify the identity: 11−sin2x=1+tan2x Verifying Trigonometric Identities: Verifying the trigonometric identities means we have to show that the left-hand side of an equation is equal to the right-hand side, or vic...
购买纸质书, 5分一面3元包邮的打印好去处, 微信与我联系, 论坛千份真题解答, ZTM丛书(诸多0元购) 思考: 在 的某个去心邻域连续, 对么? 这个命题的逆命题是对的, 因为有界量乘以无穷小量还是无穷小量. 但这命题对...
所以,如果我们知道了sin30度和cos30度的值,就可以很容易地求出tan30度。sin30度等于(frac{1}{2}),而cos30度等于(frac{sqrt{3}}{2})。那么,根据上面的公式,我们就可以计算出: [ an 30^circ = frac{sin 30^circ}{cos 30^circ} = frac{frac{1}{2}}{frac{sqrt{3}}{2}} = frac{1}{sqrt{3...
Answer to: Find: \int \left (\frac{11}{x^2} \right ) \sin^2 \left ( \frac{11}{x} \right ) \cos \left (\frac{11}{x} \right ) dx , Solve using...
Answer to: Evaluate the limit \lim_{x\rightarrow 0} \frac{e^x-1}{\sin x} By signing up, you'll get thousands of step-by-step solutions to your...
Answer to: Evaluate \lim_{{(x,y)} \rightarrow {(1,0)}} (\frac{y\ln y}{x}) , \lim_{{(x,y)} \rightarrow {(0,1)}} (\frac{y\sin x}{x(y+1)}). By...
Click here:point_up_2:to get an answer to your question :writing_hand:the value of sin left arccos left frac12 right right is
D.1 相关知识点: 试题来源: 解析 A. 1/6 该极限可以使用洛必达法则求解。由于当 x 趋近于 0 时,分子和分母都趋近于 0,满足洛必达法则的条件。对分子和分母分别求导,并重复使用洛必达法则三次,最终得到极限值为 1/6。因此,正确答案为 A. 1/6。