Given a binary tree, flatten it to a linked list in-place. For example, Given 1 / \ 2 5 / \ \ 3 4 6 The flattened tree should look like: 1 \ 2 \ 3 \ 4 \ 5 \ 6 click to show hints. Hints: If you notice carefully in the flattened tree, each node's right child points ...
https://leetcode.com/problems/flatten-binary-tree-to-linked-list/ 题目: Given a binary tree, flatten it to a linked list in-place. For example, Given 1 / \ 2 5 / \ \ 3 4 6 The flattened tree should look like: 1 \ 2 \ 3 \ 4 \ 5 \ 6 思路: 递归处理每个结点,如果结点左孩...
Given a binary tree, flatten it to a linked list in-place. For example, Given 1 / \ 2 5 / \ \ 3 4 6 The flattened tree should look like: 1 \ 2 \ 3 \ 4 \ 5 \ 6 Hints: If you notice carefully in the flattened tree, each node's right child points to the next node of ...
using namespace std; struct TreeNode { int val; TreeNode *left; TreeNode *right; TreeNode() {} TreeNode(int val) : val(val) {} TreeNode(int val, TreeNode *left, TreeNode *right) : val(val), left(left), right(right) {} }; class Solution { public: void flatten(TreeNode* ro...
114. Flatten Binary Tree to Linked List # 题目 # Given a binary tree, flatten it to a linked list in-place. For example, given the following tree: 1 / \ 2 5 / \ \ 3 4 6 The flattened tree should look like: 1 \ 2 \ 3 \ 4 \ 5 \ 6 题目大意 # 给定一个
publicvoidPrintBinaryTreeBacRecur(TreeNode<T>root){if(root==null)return;PrintBinaryTreeBacRecur(root.right);PrintBinaryTreeBacRecur(root.left);System.out.print(root.data);} 这里的话,我们不再是打印根节点,而是利用一个全局变量pre,更新当前根节点的右指针为pre,左指针为null。
LeetCode: 114. Flatten Binary Tree to Linked List 题目描述 Given a binary tree, flatten it to a linked list in-place. For example, Given 1 / \ 2 5 / \ \ 3 4 6 1. 2. 3. 4. 5. The flattened tree should look like:
一、原题114. Flatten Binary Tree to Linked List 二、前序遍历 + 展成单链 两步方式 首先通过前序遍历将节点存储到vector 中,然后将vector中的节点展成单链形式。 前序遍历(递归方式实现) /*** Definition for a binary tree node.* struct TreeNode {* int val;* TreeNode *left;* TreeNode *right...
114. Flatten Binary Tree to Linked List Given a binary tree, flatten it to a linked list in-place. For example, given the following tree: 1 / \ 2 5 / \ \ 3 4 6 The flattened tree should look like: 1 \ 2 \ 3 \ 4 \
Given a binary tree, flatten it to a linked list in-place. For example, Given 1 / \ 2 5 / \ \ 3 4 6 The flattened tree should look like: 1 \ 2 \ 3 \ 4 \ 5 \ 6 递归法 思路 相当于一次先序遍历, 将先访问的点存储在数组里, 下一个访问的节点为之前访问的点的右子树 ...