* Definition for a binary tree node. * type TreeNode struct { * Val int * Left *TreeNode * Right *TreeNode * } */// 解法一 非递归funcflatten(root*TreeNode){list,cur:=[]int{},&TreeNode{}preorder(root,&list)cur=rootfori:=1;i<len(list);i++{cur.Left=nilcur.Right=&TreeNode...
Given a binary tree, flatten it to a linked list in-place.For example,Given1 / \ 2 5 / \ \ 3 4 6 The flattened tree should look like:1 \ 2 \ 3 \ 4 \ 5 \ 6Hints: If you notice carefully in the flattened tree, each node's right child points to the next node of a ...
由于栈是先进后出,所以我们先将右节点入栈。 publicstaticvoidpreOrderStack(TreeNoderoot){if(root==null){return;}Stack<TreeNode>s=newStack<TreeNode>();s.push(root);while(!s.isEmpty()){TreeNodetemp=s.pop();System.out.println(temp.val);if(temp.right!=null){s.push(temp.right);}if(temp...
LeetCode—108. Convert Sorted Array to Binary Search Tree 题目 https://leetcode.com/problems/convert-sorted-array-to-binary-search-tree/description/ 将一个递增数组转化为平衡二叉搜索树。平衡二叉搜索树首先是一个二叉搜索树,其次要求每一个节点的左右... ...
Given a binary tree, flatten it to a linked list in-place. For example,Given The flattened tree should look like: click to show hints. Hints: If you n
要求:Given a binary tree, flatten it to a linked list in-place.将二叉树转化为平坦序列的树。比如: 结题思路: 该题有个提示,转化后的树的序列正好是二叉树前序遍历所得到的序列,所以,该题第一个思路就是利用前序遍历的方式来做。 第二个思路:我们可以利用递归的思路,先对根节点进行处理,将root的左子...
Given a binary tree, flatten it to a linked list in-place. For example, Given 代码语言:javascript 代码运行次数:0 运行 AI代码解释 1/\25/\ \346 The flattened tree should look like: 代码语言:javascript 代码运行次数:0 运行 AI代码解释 ...
也就是6作为5的右孩子,5作为4的右孩子,以此类推。 class Solution { private TreeNode prev = null; public void flatten(TreeNode root) { if (root == null) return; flatten(root.right); flatten(root.left); root.right = prev; root.left = null; prev = root; } }...
* TreeNode *left; * TreeNode *right; * TreeNode(int x) : val(x), left(NULL), right(NULL) {} * };*/classSolution {public: TreeNode* prev =NULL;voidflatten(TreeNode*root) {//using this solution:https://leetcode.com/problems/flatten-binary-tree-to-linked-list/discuss/36977/My-sh...
Given a binary tree, flatten it to a linked list in-place. For example, Given 1 / \ 2 5 / \ \ 3 4 6 The flattened tree should look like: 1 \ 2 \ 3 \ 4 \ 5 \ 6 思路: 递归处理每个结点,如果结点左孩子为空,则无需处理。否则先将结点右孩子挂到左孩子最右边的子孙结点,然后将左...